What is the general solution for cos(θ)=(4sqrt(2))/7 ,sin(θ) ?

The general solution for cos(θ)=(4sqrt(2))/7 ,sin(θ) is No Solution for θ\in\mathbb{R}

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cos(θ)=(4sqrt(2))/7 ,sin(θ)

cos (θ) = \frac{4 2}{7}, sin (θ)

No Solution for θ \in R

Solution steps

cos (θ) = \frac{4 2}{7}, sin (θ)

Apply trig inverse properties

cos (θ) = \frac{4 2}{7}

General solutions for

cos (θ) = \frac{4 2}{7}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{4 2}{7}) + 2 πn, θ = 2 π - arccos (\frac{4 2}{7}) + 2 πn

θ = arccos (\frac{4 2}{7}) + 2 πn, θ = 2 π - arccos (\frac{4 2}{7}) + 2 πn

Solutions for the range

sin (θ)

No Solution for θ \in R

arctan (\frac{1}{x - 1}) + arctan (\frac{2}{x + 1}) = \frac{π}{4}

cot (3 x) = - tan (- \frac{2 π}{5})

2 - 2 sin (x) = 3

cos (x) = \frac{60}{61}

cot (θ) = \frac{3}{8}

What is the general solution for cos(θ)=(4sqrt(2))/7 ,sin(θ) ?
The general solution for cos(θ)=(4sqrt(2))/7 ,sin(θ) is No Solution for θ\in\mathbb{R}