What is the general solution for cos(θ)=(sqrt(11))/5 ?

The general solution for cos(θ)=(sqrt(11))/5 is θ=0.84554…+2pin,θ=2pi-0.84554…+2pin

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cos(θ)=(sqrt(11))/5

cos (θ) = \frac{11}{5}

θ = 0.84554 \dots + 2 πn, θ = 2 π - 0.84554 \dots + 2 πn

Degrees

θ = 48.44605 \dots^{\circ} + 36 0^{\circ} n, θ = 311.55394 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{11}{5}

Apply trig inverse properties

cos (θ) = \frac{11}{5}

General solutions for

cos (θ) = \frac{11}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{11}{5}) + 2 πn, θ = 2 π - arccos (\frac{11}{5}) + 2 πn

θ = arccos (\frac{11}{5}) + 2 πn, θ = 2 π - arccos (\frac{11}{5}) + 2 πn

Show solutions in decimal form

θ = 0.84554 \dots + 2 πn, θ = 2 π - 0.84554 \dots + 2 πn

10 cos (θ) = 4 sin^{2} (θ) + 2

\frac{tan ^{2} ( x ) ( 1 + cot ^{2} ( x ) )}{sec ( x )} = cos (x)

4 cos^{2} (x) tan (x) - tan (x) = 0

sin (2 x) + sin^{2} (x) + cos^{2} (x) = 0

csc (x) = \frac{1}{cos ( x )}

What is the general solution for cos(θ)=(sqrt(11))/5 ?
The general solution for cos(θ)=(sqrt(11))/5 is θ=0.84554…+2pin,θ=2pi-0.84554…+2pin