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Popular Trigonometry >

solvefor x,z=arcsin((xy)/(x^2+y^2))

  • Pre Algebra
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Solution

solve for x,z=arcsin(x2+y2xy​)

Solution

x=2sin(z)y+y1−4sin2(z)​​,x=2sin(z)y−y1−4sin2(z)​​
Solution steps
z=arcsin(x2+y2xy​)
Switch sidesarcsin(x2+y2xy​)=z
Apply trig inverse properties
arcsin(x2+y2xy​)=z
arcsin(x)=a⇒x=sin(a)x2+y2xy​=sin(z)
x2+y2xy​=sin(z)
Solve x2+y2xy​=sin(z):x=2sin(z)y+y1−4sin2(z)​​,x=2sin(z)y−y1−4sin2(z)​​;sin(z)=0
x2+y2xy​=sin(z)
Multiply both sides by x2+y2
x2+y2xy​=sin(z)
Multiply both sides by x2+y2x2+y2xy​(x2+y2)=sin(z)(x2+y2)
Simplifyxy=sin(z)(x2+y2)
xy=sin(z)(x2+y2)
Solve xy=sin(z)(x2+y2):x=2sin(z)y+y1−4sin2(z)​​,x=2sin(z)y−y1−4sin2(z)​​;sin(z)=0
xy=sin(z)(x2+y2)
Expand sin(z)(x2+y2):x2sin(z)+y2sin(z)
sin(z)(x2+y2)
Apply the distributive law: a(b+c)=ab+aca=sin(z),b=x2,c=y2=sin(z)x2+sin(z)y2
=x2sin(z)+y2sin(z)
xy=x2sin(z)+y2sin(z)
Switch sidesx2sin(z)+y2sin(z)=xy
Move xyto the left side
x2sin(z)+y2sin(z)=xy
Subtract xy from both sidesx2sin(z)+y2sin(z)−xy=xy−xy
Simplifyx2sin(z)+y2sin(z)−xy=0
x2sin(z)+y2sin(z)−xy=0
Write in the standard form ax2+bx+c=0sin(z)x2−yx+y2sin(z)=0
Solve with the quadratic formula
sin(z)x2−yx+y2sin(z)=0
Quadratic Equation Formula:
For a=sin(z),b=−y,c=y2sin(z)x1,2​=2sin(z)−(−y)±(−y)2−4sin(z)y2sin(z)​​
x1,2​=2sin(z)−(−y)±(−y)2−4sin(z)y2sin(z)​​
Simplify (−y)2−4sin(z)y2sin(z)​:y1−4sin2(z)​
(−y)2−4sin(z)y2sin(z)​
(−y)2=y2
(−y)2
Apply exponent rule: (−a)n=an,if n is even(−y)2=y2=y2
4sin(z)y2sin(z)=4y2sin2(z)
4sin(z)y2sin(z)
Apply exponent rule: ab⋅ac=ab+csin(z)sin(z)=sin1+1(z)=4y2sin1+1(z)
Add the numbers: 1+1=2=4y2sin2(z)
=y2−4y2sin2(z)​
Factor out common term y2=y2(1−4sin2(z))​
Apply radical rule: assuming a≥0,b≥0=y2​−4sin2(z)+1​
Apply radical rule: assuming a≥0y2​=y=y−4sin2(z)+1​
x1,2​=2sin(z)−(−y)±y1−4sin2(z)​​;sin(z)=0
Separate the solutionsx1​=2sin(z)−(−y)+y1−4sin2(z)​​,x2​=2sin(z)−(−y)−y1−4sin2(z)​​
x=2sin(z)−(−y)+y1−4sin2(z)​​:2sin(z)y+y1−4sin2(z)​​
2sin(z)−(−y)+y1−4sin2(z)​​
Apply rule −(−a)=a=2sin(z)y+y1−4sin2(z)​​
x=2sin(z)−(−y)−y1−4sin2(z)​​:2sin(z)y−y1−4sin2(z)​​
2sin(z)−(−y)−y1−4sin2(z)​​
Apply rule −(−a)=a=2sin(z)y−y1−4sin2(z)​​
The solutions to the quadratic equation are:x=2sin(z)y+y1−4sin2(z)​​,x=2sin(z)y−y1−4sin2(z)​​;sin(z)=0
x=2sin(z)y+y1−4sin2(z)​​,x=2sin(z)y−y1−4sin2(z)​​;sin(z)=0
x=2sin(z)y+y1−4sin2(z)​​,x=2sin(z)y−y1−4sin2(z)​​

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