What is the general solution for cos^2(t)=0 ?

The general solution for cos^2(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin

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cos^2(t)=0

cos^{2} (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

cos^{2} (t) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

sin (x) = \frac{18}{12}

csc (θ) = 5

cot^{2} (x) = tan (\frac{x}{2})

cos (x) = \frac{15}{21}

2 cos (x) - cos^{2} (x) - sin^{2} (x) = 0

What is the general solution for cos^2(t)=0 ?
The general solution for cos^2(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin