What is the general solution for 3cos(x)+5=7,0<= x<= 2pi ?

The general solution for 3cos(x)+5=7,0<= x<= 2pi is x=0.84106…,x=2pi-0.84106…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos(x)+5=7,0<= x<= 2pi

3 cos (x) + 5 = 7, 0 \leq x \leq 2 π

x = 0.84106 \dots, x = 2 π - 0.84106 \dots

Degrees

x = 48.18968 \dots^{\circ}, x = 311.81031 \dots^{\circ}

Solution steps

3 cos (x) + 5 = 7, 0 \leq x \leq 2 π

Move

5

to the right side

3 cos (x) + 5 = 7

Subtract

5

from both sides

3 cos (x) + 5 - 5 = 7 - 5

Simplify

3 cos (x) = 2

3 cos (x) = 2

Divide both sides by

3

3 cos (x) = 2

Divide both sides by

3

\frac{3 cos ( x )}{3} = \frac{2}{3}

Simplify

cos (x) = \frac{2}{3}

cos (x) = \frac{2}{3}

Apply trig inverse properties

cos (x) = \frac{2}{3}

General solutions for

cos (x) = \frac{2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{2}{3}) + 2 πn, x = 2 π - arccos (\frac{2}{3}) + 2 πn

x = arccos (\frac{2}{3}) + 2 πn, x = 2 π - arccos (\frac{2}{3}) + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = arccos (\frac{2}{3}), x = 2 π - arccos (\frac{2}{3})

Show solutions in decimal form

x = 0.84106 \dots, x = 2 π - 0.84106 \dots

9 sin (\frac{x}{2}) + 9 cos (x) = 0

- 5 cos (x) + 5 sin (x) = \frac{5 2}{2}

10 sin (θ) = 4 cos^{2} (θ) + 2

cos (x) = - \frac{1}{3}

6 - 24 cos^{2} (t) = 0

What is the general solution for 3cos(x)+5=7,0<= x<= 2pi ?
The general solution for 3cos(x)+5=7,0<= x<= 2pi is x=0.84106…,x=2pi-0.84106…