What is the general solution for cos(x)= 1/(sqrt(10)) ?

The general solution for cos(x)= 1/(sqrt(10)) is x=1.24904…+2pin,x=2pi-1.24904…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x)= 1/(sqrt(10))

cos (x) = \frac{1}{10}

x = 1.24904 \dots + 2 πn, x = 2 π - 1.24904 \dots + 2 πn

Radians

x = 1.24904 \dots + 6.28318 \dots n, x = 5.03413 \dots + 6.28318 \dots n

Solution steps

cos (x) = \frac{1}{10}

Simplify

\frac{1}{10} : \frac{10}{10}

\frac{1}{10}

Multiply by the conjugate

\frac{10}{10}

= \frac{1 \cdot 10}{10 10}

1 \cdot 10 = 10

1010 = 10

1010

Apply radical rule:

a a = a

1010 = 10

= 10

= \frac{10}{10}

cos (x) = \frac{10}{10}

Apply trig inverse properties

cos (x) = \frac{10}{10}

General solutions for

cos (x) = \frac{10}{10}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{10}{10}) + 2 πn, x = 2 π - arccos (\frac{10}{10}) + 2 πn

x = arccos (\frac{10}{10}) + 2 πn, x = 2 π - arccos (\frac{10}{10}) + 2 πn

Show solutions in decimal form

x = 1.24904 \dots + 2 πn, x = 2 π - 1.24904 \dots + 2 πn

u, x = 5 sinh (u)

sin (\frac{π}{2} x) + 1 = 0

3 tan^{2} (x) - tan (x) = 0

sin (2 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

x, 2 sin (x) - 3 = 0

What is the general solution for cos(x)= 1/(sqrt(10)) ?
The general solution for cos(x)= 1/(sqrt(10)) is x=1.24904…+2pin,x=2pi-1.24904…+2pin