What is the general solution for sin(θ)= 35/37 ?

The general solution for sin(θ)= 35/37 is θ=1.24049…+2pin,θ=pi-1.24049…+2pin

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sin(θ)= 35/37

sin (θ) = \frac{35}{37}

θ = 1.24049 \dots + 2 πn, θ = π - 1.24049 \dots + 2 πn

Degrees

θ = 71.07535 \dots^{\circ} + 36 0^{\circ} n, θ = 108.92464 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{35}{37}

Apply trig inverse properties

sin (θ) = \frac{35}{37}

General solutions for

sin (θ) = \frac{35}{37}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{35}{37}) + 2 πn, θ = π - arcsin (\frac{35}{37}) + 2 πn

θ = arcsin (\frac{35}{37}) + 2 πn, θ = π - arcsin (\frac{35}{37}) + 2 πn

Show solutions in decimal form

θ = 1.24049 \dots + 2 πn, θ = π - 1.24049 \dots + 2 πn

sin^{2} (θ) = \frac{2 + 3}{4}

8 sin (c) + 3 = 3 sin (c) + 3

4 cos (x^{2}) - 1 = 0

2 cos^{2} (x) - 7 cos (x) = - 3, 0 \leq x \leq 2 π

sin (2 x) = \frac{( 4 m - 9 )}{8}

What is the general solution for sin(θ)= 35/37 ?
The general solution for sin(θ)= 35/37 is θ=1.24049…+2pin,θ=pi-1.24049…+2pin