What is the general solution for cos(α)=(sqrt(3))/2 ?

The general solution for cos(α)=(sqrt(3))/2 is α= pi/6+2pin,α=(11pi)/6+2pin

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cos(α)=(sqrt(3))/2

cos (α) = \frac{3}{2}

α = \frac{π}{6} + 2 πn, α = \frac{11 π}{6} + 2 πn

Degrees

α = 3 0^{\circ} + 36 0^{\circ} n, α = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (α) = \frac{3}{2}

General solutions for

cos (α) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

α = \frac{π}{6} + 2 πn, α = \frac{11 π}{6} + 2 πn

α = \frac{π}{6} + 2 πn, α = \frac{11 π}{6} + 2 πn

tan (t) = - \frac{4}{3}

sin^{2} (x) = 0.25

sin (x) + 3 cos (x) = 3

tan^{4} (x) = tan (x)

2 sin (θ) - csc (θ) = 1

What is the general solution for cos(α)=(sqrt(3))/2 ?
The general solution for cos(α)=(sqrt(3))/2 is α= pi/6+2pin,α=(11pi)/6+2pin