What is the general solution for 2+2cos(θ)=2 ?

The general solution for 2+2cos(θ)=2 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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2+2cos(θ)=2

2 + 2 cos (θ) = 2

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Degrees

θ = 9 0^{\circ} + 36 0^{\circ} n, θ = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

2 + 2 cos (θ) = 2

Subtract

2

from both sides

2 + 2 cos (θ) - 2 = 2 - 2

Simplify

2 cos (θ) = 0

Divide both sides by

2

2 cos (θ) = 0

Divide both sides by

2

\frac{2 cos ( θ )}{2} = \frac{0}{2}

Simplify

cos (θ) = 0

cos (θ) = 0

General solutions for

cos (θ) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

1 - sec^{2} (x) = 0

3 cot^{2} (y - \frac{π}{4}) = 1

sin^{2} (x) - tan (x) cos (x) = 0

cos (t) = - \frac{5}{13}

8 cos (x) = - 4

What is the general solution for 2+2cos(θ)=2 ?
The general solution for 2+2cos(θ)=2 is θ= pi/2+2pin,θ=(3pi)/2+2pin