What is the general solution for tan(b)=1 ?

The general solution for tan(b)=1 is b= pi/4+pin

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tan(b)=1

tan (b) = 1

b = \frac{π}{4} + πn

Degrees

b = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (b) = 1

General solutions for

tan (b) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

b = \frac{π}{4} + πn

b = \frac{π}{4} + πn

5 cos^{2} (θ) - 1 = cos^{2} (θ)

cos (x) = \frac{2}{9}

x, tan (x) + tan (y) = 1

x, 4 cos (x) cos (y) = 3

sin (x) = 0, 57

What is the general solution for tan(b)=1 ?
The general solution for tan(b)=1 is b= pi/4+pin