What is the general solution for cos(A)=-1/2 ?

The general solution for cos(A)=-1/2 is A=(2pi)/3+2pin,A=(4pi)/3+2pin

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cos(A)=-1/2

cos (A) = - \frac{1}{2}

A = \frac{2 π}{3} + 2 πn, A = \frac{4 π}{3} + 2 πn

Degrees

A = 12 0^{\circ} + 36 0^{\circ} n, A = 24 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (A) = - \frac{1}{2}

General solutions for

cos (A) = - \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

A = \frac{2 π}{3} + 2 πn, A = \frac{4 π}{3} + 2 πn

A = \frac{2 π}{3} + 2 πn, A = \frac{4 π}{3} + 2 πn

sin (x) = cos (4 x)

cos (x) = \frac{13}{12}

- 2 + cot (θ) = - 3

sin^{2} (x) + sin (x) = 0, 0 \leq x \leq 2 π

\frac{1}{tan ( x )} = - 1

What is the general solution for cos(A)=-1/2 ?
The general solution for cos(A)=-1/2 is A=(2pi)/3+2pin,A=(4pi)/3+2pin