What is the general solution for 64cosh^4(x)-64cosh^2(x)-9=0 ?

The general solution for 64cosh^4(x)-64cosh^2(x)-9=0 is x= 1/2 ln(2),x=-1/2 ln(2)

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Popular Trigonometry >

64cosh^4(x)-64cosh^2(x)-9=0

Solution

64 cosh^{4} (x) - 64 cosh^{2} (x) - 9 = 0

Solution

x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

Degrees

x = 19.85720 \dots^{\circ}, x = - 19.85720 \dots^{\circ}

Solution steps

64 cosh^{4} (x) - 64 cosh^{2} (x) - 9 = 0

Rewrite using trig identities

64 cosh^{4} (x) - 64 cosh^{2} (x) - 9 = 0

Use the Hyperbolic identity:

cosh (x) = \frac{e ^{x} + e ^{- x}}{2}

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0 : x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0

Apply exponent rules

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0

Apply exponent rule:

a^{b c} = (a^{b})^{c}

e^{- x} = (e^{x})^{- 1}

64 (\frac{e ^{x} + ( e ^{x} ) ^{- 1}}{2})^{4} - 64 (\frac{e ^{x} + ( e ^{x} ) ^{- 1}}{2})^{2} - 9 = 0

64 (\frac{e ^{x} + ( e ^{x} ) ^{- 1}}{2})^{4} - 64 (\frac{e ^{x} + ( e ^{x} ) ^{- 1}}{2})^{2} - 9 = 0

Rewrite the equation with

e^{x} = u

64 (\frac{u + ( u ) ^{- 1}}{2})^{4} - 64 (\frac{u + ( u ) ^{- 1}}{2})^{2} - 9 = 0

Solve

64 (\frac{u + u ^{- 1}}{2})^{4} - 64 (\frac{u + u ^{- 1}}{2})^{2} - 9 = 0 : u = - \frac{1}{2}, u = - 2, u = 2, u = \frac{1}{2}

64 (\frac{u + u ^{- 1}}{2})^{4} - 64 (\frac{u + u ^{- 1}}{2})^{2} - 9 = 0

Factor

64 (\frac{u + u ^{- 1}}{2})^{4} - 64 (\frac{u + u ^{- 1}}{2})^{2} - 9 : (\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (2 (u + \frac{1}{u}) + 3) (2 (u + \frac{1}{u}) - 3)

64 (\frac{u + u ^{- 1}}{2})^{4} - 64 (\frac{u + u ^{- 1}}{2})^{2} - 9

Let

u = (\frac{u + u ^{- 1}}{2})^{2}

= 64 u^{2} - 64 u - 9

Factor

64 u^{2} - 64 u - 9 : (8 u + 1) (8 u - 9)

64 u^{2} - 64 u - 9

Break the expression into groups

64 u^{2} - 64 u - 9

Definition

Factors of

576 : 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 64, 72, 96, 144, 192, 288, 576

576

Divisors (Factors)

Find the Prime factors of

576 : 2, 2, 2, 2, 2, 2, 3, 3

576

576

divides by

2576 = 288 \cdot 2

= 2 \cdot 288

288

divides by

2288 = 144 \cdot 2

= 2 \cdot 2 \cdot 144

144

divides by

2144 = 72 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 72

72

divides by

272 = 36 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 36

36

divides by

236 = 18 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 18

18

divides by

218 = 9 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 9

9

divides by

39 = 3 \cdot 3

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 \cdot 3

Multiply the prime factors of

576 : 4, 8, 16, 32, 64, 6, 12, 24, 48, 96, 192, 9, 18, 36, 72, 144, 288

2 \cdot 2 = 4

2 \cdot 2 \cdot 2 = 8

4, 8, 16, 32, 64, 6, 12, 24, 48, 96, 192, 9, 18, 36, 72, 144, 288

4, 8, 16, 32, 64, 6, 12, 24, 48, 96, 192, 9, 18, 36, 72, 144, 288

Add the prime factors:

2, 3

Add 1 and the number

576

itself

1, 576

The factors of

576

1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 64, 72, 96, 144, 192, 288, 576

Negative factors of

576 : - 1, - 2, - 3, - 4, - 6, - 8, - 9, - 12, - 16, - 18, - 24, - 32, - 36, - 48, - 64, - 72, - 96, - 144, - 192, - 288, - 576

Multiply the factors by

- 1

to get the negative factors

- 1, - 2, - 3, - 4, - 6, - 8, - 9, - 12, - 16, - 18, - 24, - 32, - 36, - 48, - 64, - 72, - 96, - 144, - 192, - 288, - 576

For every two factors such that

u * v = - 576,

check if

u + v = - 64

Check

u = 1, v = - 576 : u * v = - 576, u + v = - 575 \Rightarrow

FalseCheck

u = 2, v = - 288 : u * v = - 576, u + v = - 286 \Rightarrow

False

u = 8, v = - 72

Group into

(a x^{2} + ux) + (vx + c)

(64 u^{2} + 8 u) + (- 72 u - 9)

= (64 u^{2} + 8 u) + (- 72 u - 9)

Factor out

8 u

from

64 u^{2} + 8 u : 8 u (8 u + 1)

64 u^{2} + 8 u

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

u^{2} = uu

= 64 uu + 8 u

Rewrite

64

8 \cdot 8

= 8 \cdot 8 uu + 8 u

Factor out common term

8 u

= 8 u (8 u + 1)

Factor out

- 9

from

- 72 u - 9 : - 9 (8 u + 1)

- 72 u - 9

Rewrite

72

9 \cdot 8

= - 9 \cdot 8 u - 9

Factor out common term

- 9

= - 9 (8 u + 1)

= 8 u (8 u + 1) - 9 (8 u + 1)

Factor out common term

8 u + 1

= (8 u + 1) (8 u - 9)

= (8 u + 1) (8 u - 9)

Substitute back

u = (\frac{u + u ^{- 1}}{2})^{2}

= (8 (\frac{u + u ^{- 1}}{2})^{2} + 1) (8 (\frac{u + u ^{- 1}}{2})^{2} - 9)

Factor

8 (\frac{u + u ^{- 1}}{2})^{2} - 9 : (8 \frac{u + u ^{- 1}}{2} + 3) (8 \frac{u + u ^{- 1}}{2} - 3)

8 (\frac{u + u ^{- 1}}{2})^{2} - 9

Rewrite

8 (\frac{u + u ^{- 1}}{2})^{2} - 9

(8 \frac{u + u ^{- 1}}{2})^{2} - 3^{2}

8 (\frac{u + u ^{- 1}}{2})^{2} - 9

Apply radical rule:

a = (a)^{2}

8 = (8)^{2}

= (8)^{2} (\frac{u + u ^{- 1}}{2})^{2} - 9

Rewrite

9

3^{2}

= (8)^{2} (\frac{u + u ^{- 1}}{2})^{2} - 3^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m}

(8)^{2} (\frac{u + u ^{- 1}}{2})^{2} = (8 \frac{u + u ^{- 1}}{2})^{2}

= (8 (\frac{u + u ^{- 1}}{2}))^{2} - 3^{2}

= (8 (\frac{u + u ^{- 1}}{2}))^{2} - 3^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(8 \frac{u + u ^{- 1}}{2})^{2} - 3^{2} = (8 \frac{u + u ^{- 1}}{2} + 3) (8 \frac{u + u ^{- 1}}{2} - 3)

= (8 (\frac{u + u ^{- 1}}{2}) + 3) (8 (\frac{u + u ^{- 1}}{2}) - 3)

= (8 (\frac{u + u ^{- 1}}{2})^{2} + 1) (8 (\frac{u + u ^{- 1}}{2}) + 3) (8 (\frac{u + u ^{- 1}}{2}) - 3)

Refine

= (8 (\frac{u + u ^{- 1}}{2})^{2} + 1) (22 (\frac{u + u ^{- 1}}{2}) + 3) (22 (\frac{u + u ^{- 1}}{2}) - 3)

Simplify

(8 (\frac{u + u ^{- 1}}{2})^{2} + 1) (22 (\frac{u + u ^{- 1}}{2}) + 3) (22 (\frac{u + u ^{- 1}}{2}) - 3) : (\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (2 (u + \frac{1}{u}) + 3) (2 (u + \frac{1}{u}) - 3)

(8 (\frac{u + u ^{- 1}}{2})^{2} + 1) (22 (\frac{u + u ^{- 1}}{2}) + 3) (22 (\frac{u + u ^{- 1}}{2}) - 3)

Remove parentheses:

(a) = a

= (8 (\frac{u + u ^{- 1}}{2})^{2} + 1) (22 \frac{u + u ^{- 1}}{2} + 3) (22 \frac{u + u ^{- 1}}{2} - 3)

8 (\frac{u + u ^{- 1}}{2})^{2} = \frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}}

8 (\frac{u + u ^{- 1}}{2})^{2}

(\frac{u + u ^{- 1}}{2})^{2} = \frac{( u ^{2} + 1 ) ^{2}}{2 ^{2} u ^{2}}

(\frac{u + u ^{- 1}}{2})^{2}

\frac{u + u ^{- 1}}{2} = \frac{u ^{2} + 1}{2 u}

\frac{u + u ^{- 1}}{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{u + \frac{1}{u}}{2}

Join

u + \frac{1}{u} : \frac{u ^{2} + 1}{u}

u + \frac{1}{u}

Convert element to fraction:

u = \frac{uu}{u}

= \frac{uu}{u} + \frac{1}{u}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{uu + 1}{u}

uu + 1 = u^{2} + 1

uu + 1

uu = u^{2}

uu

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

uu = u^{1 + 1}

= u^{1 + 1}

Add the numbers:

1 + 1 = 2

= u^{2}

= u^{2} + 1

= \frac{u ^{2} + 1}{u}

= \frac{\frac{u ^{2} + 1}{u}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{u ^{2} + 1}{u \cdot 2}

= (\frac{u ^{2} + 1}{u \cdot 2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( u ^{2} + 1 ) ^{2}}{( 2 u ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2 u)^{2} = 2^{2} u^{2}

= \frac{( u ^{2} + 1 ) ^{2}}{2 ^{2} u ^{2}}

= 8 \cdot \frac{( u ^{2} + 1 ) ^{2}}{2 ^{2} u ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( u ^{2} + 1 ) ^{2} \cdot 8}{u ^{2} \cdot 2 ^{2}}

Factor

8 : 2^{3}

Factor

8 = 2^{3}

= \frac{2 ^{3} ( u ^{2} + 1 ) ^{2}}{2 ^{2} u ^{2}}

Cancel

\frac{( u ^{2} + 1 ) ^{2} \cdot 2 ^{3}}{u ^{2} \cdot 2 ^{2}} : \frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}}

\frac{( u ^{2} + 1 ) ^{2} \cdot 2 ^{3}}{u ^{2} \cdot 2 ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{3}}{2 ^{2}} = 2^{3 - 2}

= \frac{2 ^{3 - 2} ( u ^{2} + 1 ) ^{2}}{u ^{2}}

Subtract the numbers:

3 - 2 = 1

= \frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}}

= \frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}}

= (\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (22 \frac{u ^{- 1} + u}{2} + 3) (22 \frac{u ^{- 1} + u}{2} - 3)

22 \frac{u + u ^{- 1}}{2} = 2 (u + \frac{1}{u})

22 \frac{u + u ^{- 1}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( u + u ^{- 1} ) \cdot 2 2}{2}

Cancel the common factor:

2

= (u + u^{- 1}) 2

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 (u + \frac{1}{u})

= (\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (2 (u + \frac{1}{u}) + 3) (22 \frac{u ^{- 1} + u}{2} - 3)

22 \frac{u + u ^{- 1}}{2} = 2 (u + \frac{1}{u})

22 \frac{u + u ^{- 1}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( u + u ^{- 1} ) \cdot 2 2}{2}

Cancel the common factor:

2

= (u + u^{- 1}) 2

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 (u + \frac{1}{u})

= (\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (2 (u + \frac{1}{u}) + 3) (2 (u + \frac{1}{u}) - 3)

= (\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (2 (u + \frac{1}{u}) + 3) (2 (u + \frac{1}{u}) - 3)

(\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1) (2 (u + \frac{1}{u}) + 3) (2 (u + \frac{1}{u}) - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1 = 0 or 2 (u + \frac{1}{u}) + 3 = 0 or 2 (u + \frac{1}{u}) - 3 = 0

Solve

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1 = 0 :

No Solution for

u \in R

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1 = 0

Multiply both sides by

u^{2}

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} + 1 = 0

Multiply both sides by

u^{2}

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} u^{2} + 1 \cdot u^{2} = 0 \cdot u^{2}

Simplify

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} u^{2} + 1 \cdot u^{2} = 0 \cdot u^{2}

Simplify

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} u^{2} : 2 (u^{2} + 1)^{2}

\frac{2 ( u ^{2} + 1 ) ^{2}}{u ^{2}} u^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( u ^{2} + 1 ) ^{2} u ^{2}}{u ^{2}}

Cancel the common factor:

u^{2}

= 2 (u^{2} + 1)^{2}

Simplify

1 \cdot u^{2} : u^{2}

1 \cdot u^{2}

Multiply:

1 \cdot u^{2} = u^{2}

= u^{2}

Simplify

0 \cdot u^{2} : 0

0 \cdot u^{2}

Apply rule

0 \cdot a = 0

= 0

2 (u^{2} + 1)^{2} + u^{2} = 0

2 (u^{2} + 1)^{2} + u^{2} = 0

2 (u^{2} + 1)^{2} + u^{2} = 0

Solve

2 (u^{2} + 1)^{2} + u^{2} = 0 :

No Solution for

u \in R

2 (u^{2} + 1)^{2} + u^{2} = 0

Expand

2 (u^{2} + 1)^{2} + u^{2} : 2 u^{4} + 5 u^{2} + 2

2 (u^{2} + 1)^{2} + u^{2}

(u^{2} + 1)^{2} = u^{4} + 2 u^{2} + 1

(u^{2} + 1)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = u^{2}, b = 1

= (u^{2})^{2} + 2 u^{2} \cdot 1 + 1^{2}

Simplify

(u^{2})^{2} + 2 u^{2} \cdot 1 + 1^{2} : u^{4} + 2 u^{2} + 1

(u^{2})^{2} + 2 u^{2} \cdot 1 + 1^{2}

Apply rule

1^{a} = 1

1^{2} = 1

= (u^{2})^{2} + 2 \cdot 1 \cdot u^{2} + 1

(u^{2})^{2} = u^{4}

(u^{2})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= u^{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= u^{4}

2 u^{2} \cdot 1 = 2 u^{2}

2 u^{2} \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2 u^{2}

= u^{4} + 2 u^{2} + 1

= u^{4} + 2 u^{2} + 1

= 2 (u^{4} + 2 u^{2} + 1) + u^{2}

Expand

2 (u^{4} + 2 u^{2} + 1) : 2 u^{4} + 4 u^{2} + 2

2 (u^{4} + 2 u^{2} + 1)

Distribute parentheses

= 2 u^{4} + 2 \cdot 2 u^{2} + 2 \cdot 1

Simplify

2 u^{4} + 2 \cdot 2 u^{2} + 2 \cdot 1 : 2 u^{4} + 4 u^{2} + 2

2 u^{4} + 2 \cdot 2 u^{2} + 2 \cdot 1

Multiply the numbers:

2 \cdot 2 = 4

= 2 u^{4} + 4 u^{2} + 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2 u^{4} + 4 u^{2} + 2

= 2 u^{4} + 4 u^{2} + 2

= 2 u^{4} + 4 u^{2} + 2 + u^{2}

Simplify

2 u^{4} + 4 u^{2} + 2 + u^{2} : 2 u^{4} + 5 u^{2} + 2

2 u^{4} + 4 u^{2} + 2 + u^{2}

Group like terms

= 2 u^{4} + 4 u^{2} + u^{2} + 2

Add similar elements:

4 u^{2} + u^{2} = 5 u^{2}

= 2 u^{4} + 5 u^{2} + 2

= 2 u^{4} + 5 u^{2} + 2

2 u^{4} + 5 u^{2} + 2 = 0

Rewrite the equation with

v = u^{2}

and

v^{2} = u^{4}

2 v^{2} + 5 v + 2 = 0

Solve

2 v^{2} + 5 v + 2 = 0 : v = - \frac{1}{2}, v = - 2

2 v^{2} + 5 v + 2 = 0

Solve with the quadratic formula

2 v^{2} + 5 v + 2 = 0

Quadratic Equation Formula:

For

a = 2, b = 5, c = 2

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

5^{2} - 4 \cdot 2 \cdot 2

Multiply the numbers:

4 \cdot 2 \cdot 2 = 16

= 5^{2} - 16

5^{2} = 25

= 25 - 16

Subtract the numbers:

25 - 16 = 9

= 9

Factor the number:

9 = 3^{2}

= 3^{2}

Apply radical rule:

3^{2} = 3

= 3

v_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 5 + 3}{2 \cdot 2}, v_{2} = \frac{- 5 - 3}{2 \cdot 2}

v = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

\frac{- 5 + 3}{2 \cdot 2}

Add/Subtract the numbers:

- 5 + 3 = - 2

= \frac{- 2}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{- 2}{4}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{4}

Cancel the common factor:

2

= - \frac{1}{2}

v = \frac{- 5 - 3}{2 \cdot 2} : - 2

\frac{- 5 - 3}{2 \cdot 2}

Subtract the numbers:

- 5 - 3 = - 8

= \frac{- 8}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{- 8}{4}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8}{4}

Divide the numbers:

\frac{8}{4} = 2

= - 2

The solutions to the quadratic equation are:

v = - \frac{1}{2}, v = - 2

v = - \frac{1}{2}, v = - 2

Substitute back

v = u^{2},

solve for

u

Solve

u^{2} = - \frac{1}{2} :

No Solution for

u \in R

u^{2} = - \frac{1}{2}

x^{2}

cannot be negative for

x \in R

No Solution for u \in R

Solve

u^{2} = - 2 :

No Solution for

u \in R

u^{2} = - 2

x^{2}

cannot be negative for

x \in R

No Solution for u \in R

The solution is

No Solution for u \in R

No Solution for u \in R

Solve

2 (u + \frac{1}{u}) + 3 = 0 : u = - \frac{1}{2}, u = - 2

2 (u + \frac{1}{u}) + 3 = 0

Expand

2 (u + \frac{1}{u}) + 3 : 2 u + \frac{2}{u} + 3

2 (u + \frac{1}{u}) + 3

Expand

2 (u + \frac{1}{u}) : 2 u + \frac{2}{u}

2 (u + \frac{1}{u})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = u, c = \frac{1}{u}

= 2 u + 2 \frac{1}{u}

2 \frac{1}{u} = \frac{2}{u}

2 \frac{1}{u}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{u}

Multiply:

1 \cdot 2 = 2

= \frac{2}{u}

= 2 u + \frac{2}{u}

= 2 u + \frac{2}{u} + 3

2 u + \frac{2}{u} + 3 = 0

Multiply both sides by

u

2 u + \frac{2}{u} + 3 = 0

Multiply both sides by

u

2 uu + \frac{2}{u} u + 3 u = 0 \cdot u

Simplify

2 uu + \frac{2}{u} u + 3 u = 0 \cdot u

Simplify

2 uu : 2 u^{2}

2 uu

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

uu = u^{1 + 1}

= 2 u^{1 + 1}

Add the numbers:

1 + 1 = 2

= 2 u^{2}

Simplify

\frac{2}{u} u : 2

\frac{2}{u} u

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 u}{u}

Cancel the common factor:

u

= 2

Simplify

0 \cdot u : 0

0 \cdot u

Apply rule

0 \cdot a = 0

= 0

2 u^{2} + 2 + 3 u = 0

2 u^{2} + 2 + 3 u = 0

2 u^{2} + 2 + 3 u = 0

Solve

2 u^{2} + 2 + 3 u = 0 : u = - \frac{1}{2}, u = - 2

2 u^{2} + 2 + 3 u = 0

Write in the standard form

a x^{2} + b x + c = 0

2 u^{2} + 3 u + 2 = 0

Solve with the quadratic formula

2 u^{2} + 3 u + 2 = 0

Quadratic Equation Formula:

For

a = 2, b = 3, c = 2

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 2 2}{2 2}

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 2 2}{2 2}

3^{2} - 422 = 1

3^{2} - 422

422 = 8

422

Apply radical rule:

a a = a

22 = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= 3^{2} - 8

3^{2} = 9

= 9 - 8

Subtract the numbers:

9 - 8 = 1

= 1

Apply rule

1 = 1

= 1

u_{1, 2} = \frac{- 3 \pm 1}{2 2}

Separate the solutions

u_{1} = \frac{- 3 + 1}{2 2}, u_{2} = \frac{- 3 - 1}{2 2}

u = \frac{- 3 + 1}{2 2} : - \frac{1}{2}

\frac{- 3 + 1}{2 2}

Add/Subtract the numbers:

- 3 + 1 = - 2

= \frac{- 2}{2 2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{2 2}

Divide the numbers:

\frac{2}{2} = 1

= - \frac{1}{2}

u = \frac{- 3 - 1}{2 2} : - 2

\frac{- 3 - 1}{2 2}

Subtract the numbers:

- 3 - 1 = - 4

= \frac{- 4}{2 2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{2 2}

Divide the numbers:

\frac{4}{2} = 2

= \frac{2}{2}

Apply radical rule:

2 = 2^{\frac{1}{2}}

= \frac{2}{2 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{1}}{2 ^{\frac{1}{2}}} = 2^{1 - \frac{1}{2}}

= 2^{1 - \frac{1}{2}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= 2^{\frac{1}{2}}

Apply radical rule:

2^{\frac{1}{2}} = 2

= - 2

The solutions to the quadratic equation are:

u = - \frac{1}{2}, u = - 2

u = - \frac{1}{2}, u = - 2

Verify Solutions

Find undefined (singularity) points:

u = 0

Take the denominator(s) of

2 (u + \frac{1}{u}) + 3

and compare to zero

u = 0

The following points are undefined

u = 0

Combine undefined points with solutions:

u = - \frac{1}{2}, u = - 2

Solve

2 (u + \frac{1}{u}) - 3 = 0 : u = 2, u = \frac{1}{2}

2 (u + \frac{1}{u}) - 3 = 0

Expand

2 (u + \frac{1}{u}) - 3 : 2 u + \frac{2}{u} - 3

2 (u + \frac{1}{u}) - 3

Expand

2 (u + \frac{1}{u}) : 2 u + \frac{2}{u}

2 (u + \frac{1}{u})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = u, c = \frac{1}{u}

= 2 u + 2 \frac{1}{u}

2 \frac{1}{u} = \frac{2}{u}

2 \frac{1}{u}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{u}

Multiply:

1 \cdot 2 = 2

= \frac{2}{u}

= 2 u + \frac{2}{u}

= 2 u + \frac{2}{u} - 3

2 u + \frac{2}{u} - 3 = 0

Multiply both sides by

u

2 u + \frac{2}{u} - 3 = 0

Multiply both sides by

u

2 uu + \frac{2}{u} u - 3 u = 0 \cdot u

Simplify

2 uu + \frac{2}{u} u - 3 u = 0 \cdot u

Simplify

2 uu : 2 u^{2}

2 uu

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

uu = u^{1 + 1}

= 2 u^{1 + 1}

Add the numbers:

1 + 1 = 2

= 2 u^{2}

Simplify

\frac{2}{u} u : 2

\frac{2}{u} u

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 u}{u}

Cancel the common factor:

u

= 2

Simplify

0 \cdot u : 0

0 \cdot u

Apply rule

0 \cdot a = 0

= 0

2 u^{2} + 2 - 3 u = 0

2 u^{2} + 2 - 3 u = 0

2 u^{2} + 2 - 3 u = 0

Solve

2 u^{2} + 2 - 3 u = 0 : u = 2, u = \frac{1}{2}

2 u^{2} + 2 - 3 u = 0

Write in the standard form

a x^{2} + b x + c = 0

2 u^{2} - 3 u + 2 = 0

Solve with the quadratic formula

2 u^{2} - 3 u + 2 = 0

Quadratic Equation Formula:

For

a = 2, b = - 3, c = 2

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 2 2}{2 2}

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 2 2}{2 2}

(- 3)^{2} - 422 = 1

(- 3)^{2} - 422

(- 3)^{2} = 3^{2}

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2}

= 3^{2}

422 = 8

422

Apply radical rule:

a a = a

22 = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= 3^{2} - 8

3^{2} = 9

= 9 - 8

Subtract the numbers:

9 - 8 = 1

= 1

Apply rule

1 = 1

= 1

u_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 2}

Separate the solutions

u_{1} = \frac{- ( - 3 ) + 1}{2 2}, u_{2} = \frac{- ( - 3 ) - 1}{2 2}

u = \frac{- ( - 3 ) + 1}{2 2} : 2

\frac{- ( - 3 ) + 1}{2 2}

Apply rule

- (- a) = a

= \frac{3 + 1}{2 2}

Add the numbers:

3 + 1 = 4

= \frac{4}{2 2}

Divide the numbers:

\frac{4}{2} = 2

= \frac{2}{2}

Apply radical rule:

2 = 2^{\frac{1}{2}}

= \frac{2}{2 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{1}}{2 ^{\frac{1}{2}}} = 2^{1 - \frac{1}{2}}

= 2^{1 - \frac{1}{2}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= 2^{\frac{1}{2}}

Apply radical rule:

2^{\frac{1}{2}} = 2

= 2

u = \frac{- ( - 3 ) - 1}{2 2} : \frac{1}{2}

\frac{- ( - 3 ) - 1}{2 2}

Apply rule

- (- a) = a

= \frac{3 - 1}{2 2}

Subtract the numbers:

3 - 1 = 2

= \frac{2}{2 2}

Divide the numbers:

\frac{2}{2} = 1

= \frac{1}{2}

The solutions to the quadratic equation are:

u = 2, u = \frac{1}{2}

u = 2, u = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

u = 0

Take the denominator(s) of

2 (u + \frac{1}{u}) - 3

and compare to zero

u = 0

The following points are undefined

u = 0

Combine undefined points with solutions:

u = 2, u = \frac{1}{2}

Verify Solutions:

u = - \frac{1}{2}

True

, u = - 2

True

, u = 2

True

, u = \frac{1}{2}

True

Check the solutions by plugging them into

64 (\frac{u + u ^{- 1}}{2})^{4} - 64 (\frac{u + u ^{- 1}}{2})^{2} - 9 = 0

Remove the ones that don't agree with the equation.

Plug in

u = - \frac{1}{2} :

True

64 \frac{( - \frac{1}{2} ) + ( - \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{( - \frac{1}{2} ) + ( - \frac{1}{2} ) ^{- 1}}{2}^{2} - 9 = 0

64 \frac{( - \frac{1}{2} ) + ( - \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{( - \frac{1}{2} ) + ( - \frac{1}{2} ) ^{- 1}}{2}^{2} - 9 = 0

64 \frac{( - \frac{1}{2} ) + ( - \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{( - \frac{1}{2} ) + ( - \frac{1}{2} ) ^{- 1}}{2}^{2} - 9

Remove parentheses:

(- a) = - a

= 64 \frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{2} - 9

64 \frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{4} = 81

64 \frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{4}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{4} = \frac{3 ^{4}}{2 ^{6}}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{4}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2} = - \frac{3}{2 2}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}

- \frac{1}{2} + (- \frac{1}{2})^{- 1} = - \frac{1}{2} - (\frac{1}{2})^{- 1}

- \frac{1}{2} + (- \frac{1}{2})^{- 1}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- \frac{1}{2})^{- 1} = - (\frac{1}{2})^{- 1}

= - \frac{1}{2} - (\frac{1}{2})^{- 1}

= \frac{- \frac{1}{2} - ( \frac{1}{2} ) ^{- 1}}{2}

(\frac{1}{2})^{- 1} = 2

(\frac{1}{2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{\frac{1}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2

= \frac{- \frac{1}{2} - 2}{2}

Join

- \frac{1}{2} - 2 : - \frac{3}{2}

- \frac{1}{2} - 2

Convert element to fraction:

2 = \frac{2 2}{2}

= - \frac{1}{2} - \frac{2 2}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 - 2 2}{2}

- 1 - 22 = - 3

- 1 - 22

Apply radical rule:

a a = a

22 = 2

= - 1 - 2

Subtract the numbers:

- 1 - 2 = - 3

= - 3

= \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{2}

= \frac{- \frac{3}{2}}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2}}{2} = \frac{3}{2 \cdot 2}

= - \frac{3}{2 \cdot 2}

= (- \frac{3}{2 2})^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{2 2})^{4} = (\frac{3}{2 \cdot 2})^{4}

= (\frac{3}{2 \cdot 2})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{4}}{( 2 2 ) ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{4} = 2^{4} (2)^{4}

= \frac{3 ^{4}}{2 ^{4} ( 2 ) ^{4}}

(2)^{4} : 2^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 4}

\frac{1}{2} \cdot 4 = 2

\frac{1}{2} \cdot 4

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2^{2}

= \frac{3 ^{4}}{2 ^{2} \cdot 2 ^{4}}

2^{2} \cdot 2^{4} = 2^{6}

2^{2} \cdot 2^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{2} \cdot 2^{4} = 2^{2 + 4}

= 2^{2 + 4}

Add the numbers:

2 + 4 = 6

= 2^{6}

= \frac{3 ^{4}}{2 ^{6}}

= 64 \cdot \frac{3 ^{4}}{2 ^{6}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{4} \cdot 64}{2 ^{6}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{4}}{2 ^{6}}

Cancel the common factor:

2^{6}

= 3^{4}

3^{4} = 81

= 81

64 \frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{2} = 72

64 \frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{2}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{2} = \frac{3 ^{2}}{2 ^{3}}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}^{2}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2} = - \frac{3}{2 2}

\frac{- \frac{1}{2} + ( - \frac{1}{2} ) ^{- 1}}{2}

- \frac{1}{2} + (- \frac{1}{2})^{- 1} = - \frac{1}{2} - (\frac{1}{2})^{- 1}

- \frac{1}{2} + (- \frac{1}{2})^{- 1}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- \frac{1}{2})^{- 1} = - (\frac{1}{2})^{- 1}

= - \frac{1}{2} - (\frac{1}{2})^{- 1}

= \frac{- \frac{1}{2} - ( \frac{1}{2} ) ^{- 1}}{2}

(\frac{1}{2})^{- 1} = 2

(\frac{1}{2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{\frac{1}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2

= \frac{- \frac{1}{2} - 2}{2}

Join

- \frac{1}{2} - 2 : - \frac{3}{2}

- \frac{1}{2} - 2

Convert element to fraction:

2 = \frac{2 2}{2}

= - \frac{1}{2} - \frac{2 2}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 - 2 2}{2}

- 1 - 22 = - 3

- 1 - 22

Apply radical rule:

a a = a

22 = 2

= - 1 - 2

Subtract the numbers:

- 1 - 2 = - 3

= - 3

= \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{2}

= \frac{- \frac{3}{2}}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2}}{2} = \frac{3}{2 \cdot 2}

= - \frac{3}{2 \cdot 2}

= (- \frac{3}{2 2})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{2 2})^{2} = (\frac{3}{2 \cdot 2})^{2}

= (\frac{3}{2 \cdot 2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{2}}{( 2 2 ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{2} = 2^{2} (2)^{2}

= \frac{3 ^{2}}{2 ^{2} ( 2 ) ^{2}}

(2)^{2} : 2

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 2

= \frac{3 ^{2}}{2 \cdot 2 ^{2}}

2 \cdot 2^{2} = 2^{3}

2 \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{2} = 2^{1 + 2}

= 2^{1 + 2}

Add the numbers:

1 + 2 = 3

= 2^{3}

= \frac{3 ^{2}}{2 ^{3}}

= 64 \cdot \frac{3 ^{2}}{2 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{2} \cdot 64}{2 ^{3}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{2}}{2 ^{3}}

Cancel

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}} : 2^{3} \cdot 3^{2}

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{6}}{2 ^{3}} = 2^{6 - 3}

= 3^{2} \cdot 2^{6 - 3}

Subtract the numbers:

6 - 3 = 3

= 2^{3} \cdot 3^{2}

= 2^{3} \cdot 3^{2}

2^{3} = 8

= 3^{2} \cdot 8

3^{2} = 9

= 8 \cdot 9

Multiply the numbers:

8 \cdot 9 = 72

= 72

= 81 - 72 - 9

Subtract the numbers:

81 - 72 - 9 = 0

= 0

0 = 0

True

Plug in

u = - 2 :

True

64 (\frac{( - 2 ) + ( - 2 ) ^{- 1}}{2})^{4} - 64 (\frac{( - 2 ) + ( - 2 ) ^{- 1}}{2})^{2} - 9 = 0

64 (\frac{( - 2 ) + ( - 2 ) ^{- 1}}{2})^{4} - 64 (\frac{( - 2 ) + ( - 2 ) ^{- 1}}{2})^{2} - 9 = 0

64 (\frac{( - 2 ) + ( - 2 ) ^{- 1}}{2})^{4} - 64 (\frac{( - 2 ) + ( - 2 ) ^{- 1}}{2})^{2} - 9

Remove parentheses:

(- a) = - a

= 64 (\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{4} - 64 (\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{2} - 9

64 (\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{4} = 81

64 (\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{4}

(\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{4} = \frac{3 ^{4}}{2 ^{6}}

(\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{4}

\frac{- 2 + ( - 2 ) ^{- 1}}{2} = - \frac{3}{2 2}

\frac{- 2 + ( - 2 ) ^{- 1}}{2}

- 2 + (- 2)^{- 1} = - 2 - (2)^{- 1}

- 2 + (- 2)^{- 1}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{- 1} = - (2)^{- 1}

= - 2 - (2)^{- 1}

= \frac{- 2 - ( 2 ) ^{- 1}}{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{- 2 - \frac{1}{2}}{2}

Join

- 2 - \frac{1}{2} : - \frac{3}{2}

- 2 - \frac{1}{2}

Convert element to fraction:

2 = \frac{2 2}{2}

= - \frac{2 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 2 - 1}{2}

- 22 - 1 = - 3

- 22 - 1

Apply radical rule:

a a = a

22 = 2

= - 2 - 1

Subtract the numbers:

- 2 - 1 = - 3

= - 3

= \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{2}

= \frac{- \frac{3}{2}}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2}}{2} = \frac{3}{2 \cdot 2}

= - \frac{3}{2 \cdot 2}

= (- \frac{3}{2 2})^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{2 2})^{4} = (\frac{3}{2 \cdot 2})^{4}

= (\frac{3}{2 \cdot 2})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{4}}{( 2 2 ) ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{4} = 2^{4} (2)^{4}

= \frac{3 ^{4}}{2 ^{4} ( 2 ) ^{4}}

(2)^{4} : 2^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 4}

\frac{1}{2} \cdot 4 = 2

\frac{1}{2} \cdot 4

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2^{2}

= \frac{3 ^{4}}{2 ^{2} \cdot 2 ^{4}}

2^{2} \cdot 2^{4} = 2^{6}

2^{2} \cdot 2^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{2} \cdot 2^{4} = 2^{2 + 4}

= 2^{2 + 4}

Add the numbers:

2 + 4 = 6

= 2^{6}

= \frac{3 ^{4}}{2 ^{6}}

= 64 \cdot \frac{3 ^{4}}{2 ^{6}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{4} \cdot 64}{2 ^{6}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{4}}{2 ^{6}}

Cancel the common factor:

2^{6}

= 3^{4}

3^{4} = 81

= 81

64 (\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{2} = 72

64 (\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{2}

(\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{2} = \frac{3 ^{2}}{2 ^{3}}

(\frac{- 2 + ( - 2 ) ^{- 1}}{2})^{2}

\frac{- 2 + ( - 2 ) ^{- 1}}{2} = - \frac{3}{2 2}

\frac{- 2 + ( - 2 ) ^{- 1}}{2}

- 2 + (- 2)^{- 1} = - 2 - (2)^{- 1}

- 2 + (- 2)^{- 1}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{- 1} = - (2)^{- 1}

= - 2 - (2)^{- 1}

= \frac{- 2 - ( 2 ) ^{- 1}}{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{- 2 - \frac{1}{2}}{2}

Join

- 2 - \frac{1}{2} : - \frac{3}{2}

- 2 - \frac{1}{2}

Convert element to fraction:

2 = \frac{2 2}{2}

= - \frac{2 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 2 - 1}{2}

- 22 - 1 = - 3

- 22 - 1

Apply radical rule:

a a = a

22 = 2

= - 2 - 1

Subtract the numbers:

- 2 - 1 = - 3

= - 3

= \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{2}

= \frac{- \frac{3}{2}}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2}}{2} = \frac{3}{2 \cdot 2}

= - \frac{3}{2 \cdot 2}

= (- \frac{3}{2 2})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{2 2})^{2} = (\frac{3}{2 \cdot 2})^{2}

= (\frac{3}{2 \cdot 2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{2}}{( 2 2 ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{2} = 2^{2} (2)^{2}

= \frac{3 ^{2}}{2 ^{2} ( 2 ) ^{2}}

(2)^{2} : 2

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 2

= \frac{3 ^{2}}{2 \cdot 2 ^{2}}

2 \cdot 2^{2} = 2^{3}

2 \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{2} = 2^{1 + 2}

= 2^{1 + 2}

Add the numbers:

1 + 2 = 3

= 2^{3}

= \frac{3 ^{2}}{2 ^{3}}

= 64 \cdot \frac{3 ^{2}}{2 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{2} \cdot 64}{2 ^{3}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{2}}{2 ^{3}}

Cancel

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}} : 2^{3} \cdot 3^{2}

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{6}}{2 ^{3}} = 2^{6 - 3}

= 3^{2} \cdot 2^{6 - 3}

Subtract the numbers:

6 - 3 = 3

= 2^{3} \cdot 3^{2}

= 2^{3} \cdot 3^{2}

2^{3} = 8

= 3^{2} \cdot 8

3^{2} = 9

= 8 \cdot 9

Multiply the numbers:

8 \cdot 9 = 72

= 72

= 81 - 72 - 9

Subtract the numbers:

81 - 72 - 9 = 0

= 0

0 = 0

True

Plug in

u = 2 :

True

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{4} - 64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{2} - 9 = 0

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{4} - 64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{2} - 9 = 0

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{4} - 64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{2} - 9

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{4} = 81

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{4}

(\frac{2 + ( 2 ) ^{- 1}}{2})^{4} = \frac{3 ^{4}}{2 ^{6}}

(\frac{2 + ( 2 ) ^{- 1}}{2})^{4}

\frac{2 + ( 2 ) ^{- 1}}{2} = \frac{3}{2 2}

\frac{2 + ( 2 ) ^{- 1}}{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{2 + \frac{1}{2}}{2}

Join

2 + \frac{1}{2} : \frac{3}{2}

2 + \frac{1}{2}

Convert element to fraction:

2 = \frac{2 2}{2}

= \frac{2 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 2 + 1}{2}

22 + 1 = 3

22 + 1

Apply radical rule:

a a = a

22 = 2

= 2 + 1

Add the numbers:

2 + 1 = 3

= 3

= \frac{3}{2}

= \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2}

= (\frac{3}{2 \cdot 2})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{4}}{( 2 2 ) ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{4} = 2^{4} (2)^{4}

= \frac{3 ^{4}}{2 ^{4} ( 2 ) ^{4}}

(2)^{4} : 2^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 4}

\frac{1}{2} \cdot 4 = 2

\frac{1}{2} \cdot 4

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2^{2}

= \frac{3 ^{4}}{2 ^{2} \cdot 2 ^{4}}

2^{2} \cdot 2^{4} = 2^{6}

2^{2} \cdot 2^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{2} \cdot 2^{4} = 2^{2 + 4}

= 2^{2 + 4}

Add the numbers:

2 + 4 = 6

= 2^{6}

= \frac{3 ^{4}}{2 ^{6}}

= 64 \cdot \frac{3 ^{4}}{2 ^{6}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{4} \cdot 64}{2 ^{6}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{4}}{2 ^{6}}

Cancel the common factor:

2^{6}

= 3^{4}

3^{4} = 81

= 81

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{2} = 72

64 (\frac{2 + ( 2 ) ^{- 1}}{2})^{2}

(\frac{2 + ( 2 ) ^{- 1}}{2})^{2} = \frac{3 ^{2}}{2 ^{3}}

(\frac{2 + ( 2 ) ^{- 1}}{2})^{2}

\frac{2 + ( 2 ) ^{- 1}}{2} = \frac{3}{2 2}

\frac{2 + ( 2 ) ^{- 1}}{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{2 + \frac{1}{2}}{2}

Join

2 + \frac{1}{2} : \frac{3}{2}

2 + \frac{1}{2}

Convert element to fraction:

2 = \frac{2 2}{2}

= \frac{2 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 2 + 1}{2}

22 + 1 = 3

22 + 1

Apply radical rule:

a a = a

22 = 2

= 2 + 1

Add the numbers:

2 + 1 = 3

= 3

= \frac{3}{2}

= \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2}

= (\frac{3}{2 \cdot 2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{2}}{( 2 2 ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{2} = 2^{2} (2)^{2}

= \frac{3 ^{2}}{2 ^{2} ( 2 ) ^{2}}

(2)^{2} : 2

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 2

= \frac{3 ^{2}}{2 \cdot 2 ^{2}}

2 \cdot 2^{2} = 2^{3}

2 \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{2} = 2^{1 + 2}

= 2^{1 + 2}

Add the numbers:

1 + 2 = 3

= 2^{3}

= \frac{3 ^{2}}{2 ^{3}}

= 64 \cdot \frac{3 ^{2}}{2 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{2} \cdot 64}{2 ^{3}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{2}}{2 ^{3}}

Cancel

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}} : 2^{3} \cdot 3^{2}

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{6}}{2 ^{3}} = 2^{6 - 3}

= 3^{2} \cdot 2^{6 - 3}

Subtract the numbers:

6 - 3 = 3

= 2^{3} \cdot 3^{2}

= 2^{3} \cdot 3^{2}

2^{3} = 8

= 3^{2} \cdot 8

3^{2} = 9

= 8 \cdot 9

Multiply the numbers:

8 \cdot 9 = 72

= 72

= 81 - 72 - 9

Subtract the numbers:

81 - 72 - 9 = 0

= 0

0 = 0

True

Plug in

u = \frac{1}{2} :

True

64 \frac{( \frac{1}{2} ) + ( \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{( \frac{1}{2} ) + ( \frac{1}{2} ) ^{- 1}}{2}^{2} - 9 = 0

64 \frac{( \frac{1}{2} ) + ( \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{( \frac{1}{2} ) + ( \frac{1}{2} ) ^{- 1}}{2}^{2} - 9 = 0

64 \frac{( \frac{1}{2} ) + ( \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{( \frac{1}{2} ) + ( \frac{1}{2} ) ^{- 1}}{2}^{2} - 9

Remove parentheses:

(a) = a

= 64 \frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{4} - 64 \frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{2} - 9

64 \frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{4} = 81

64 \frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{4}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{4} = \frac{3 ^{4}}{2 ^{6}}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{4}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2} = \frac{3}{2 2}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}

(\frac{1}{2})^{- 1} = 2

(\frac{1}{2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{\frac{1}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2

= \frac{\frac{1}{2} + 2}{2}

Join

\frac{1}{2} + 2 : \frac{3}{2}

\frac{1}{2} + 2

Convert element to fraction:

2 = \frac{2 2}{2}

= \frac{1}{2} + \frac{2 2}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 2 2}{2}

1 + 22 = 3

1 + 22

Apply radical rule:

a a = a

22 = 2

= 1 + 2

Add the numbers:

1 + 2 = 3

= 3

= \frac{3}{2}

= \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2}

= (\frac{3}{2 \cdot 2})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{4}}{( 2 2 ) ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{4} = 2^{4} (2)^{4}

= \frac{3 ^{4}}{2 ^{4} ( 2 ) ^{4}}

(2)^{4} : 2^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 4}

\frac{1}{2} \cdot 4 = 2

\frac{1}{2} \cdot 4

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2^{2}

= \frac{3 ^{4}}{2 ^{2} \cdot 2 ^{4}}

2^{2} \cdot 2^{4} = 2^{6}

2^{2} \cdot 2^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{2} \cdot 2^{4} = 2^{2 + 4}

= 2^{2 + 4}

Add the numbers:

2 + 4 = 6

= 2^{6}

= \frac{3 ^{4}}{2 ^{6}}

= 64 \cdot \frac{3 ^{4}}{2 ^{6}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{4} \cdot 64}{2 ^{6}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{4}}{2 ^{6}}

Cancel the common factor:

2^{6}

= 3^{4}

3^{4} = 81

= 81

64 \frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{2} = 72

64 \frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{2}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{2} = \frac{3 ^{2}}{2 ^{3}}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}^{2}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2} = \frac{3}{2 2}

\frac{\frac{1}{2} + ( \frac{1}{2} ) ^{- 1}}{2}

(\frac{1}{2})^{- 1} = 2

(\frac{1}{2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{\frac{1}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2

= \frac{\frac{1}{2} + 2}{2}

Join

\frac{1}{2} + 2 : \frac{3}{2}

\frac{1}{2} + 2

Convert element to fraction:

2 = \frac{2 2}{2}

= \frac{1}{2} + \frac{2 2}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 2 2}{2}

1 + 22 = 3

1 + 22

Apply radical rule:

a a = a

22 = 2

= 1 + 2

Add the numbers:

1 + 2 = 3

= 3

= \frac{3}{2}

= \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2}

= (\frac{3}{2 \cdot 2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{3 ^{2}}{( 2 2 ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(22)^{2} = 2^{2} (2)^{2}

= \frac{3 ^{2}}{2 ^{2} ( 2 ) ^{2}}

(2)^{2} : 2

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 2

= \frac{3 ^{2}}{2 \cdot 2 ^{2}}

2 \cdot 2^{2} = 2^{3}

2 \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{2} = 2^{1 + 2}

= 2^{1 + 2}

Add the numbers:

1 + 2 = 3

= 2^{3}

= \frac{3 ^{2}}{2 ^{3}}

= 64 \cdot \frac{3 ^{2}}{2 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{2} \cdot 64}{2 ^{3}}

Factor

64 : 2^{6}

Factor

64 = 2^{6}

= \frac{2 ^{6} \cdot 3 ^{2}}{2 ^{3}}

Cancel

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}} : 2^{3} \cdot 3^{2}

\frac{3 ^{2} \cdot 2 ^{6}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{6}}{2 ^{3}} = 2^{6 - 3}

= 3^{2} \cdot 2^{6 - 3}

Subtract the numbers:

6 - 3 = 3

= 2^{3} \cdot 3^{2}

= 2^{3} \cdot 3^{2}

2^{3} = 8

= 3^{2} \cdot 8

3^{2} = 9

= 8 \cdot 9

Multiply the numbers:

8 \cdot 9 = 72

= 72

= 81 - 72 - 9

Subtract the numbers:

81 - 72 - 9 = 0

= 0

0 = 0

True

The solutions are

u = - \frac{1}{2}, u = - 2, u = 2, u = \frac{1}{2}

u = - \frac{1}{2}, u = - 2, u = 2, u = \frac{1}{2}

Substitute back

u = e^{x},

solve for

x

Solve

e^{x} = - \frac{1}{2} :

No Solution for

x \in R

e^{x} = - \frac{1}{2}

Apply exponent rules

e^{x} = - \frac{1}{2}

Apply exponent rule:

\frac{1}{a ^{b}} = a^{- b}

\frac{1}{2} = 2^{- \frac{1}{2}}

e^{x} = - 2^{- \frac{1}{2}}

e^{x} = - 2^{- \frac{1}{2}}

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

Solve

e^{x} = - 2 :

No Solution for

x \in R

e^{x} = - 2

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

Solve

e^{x} = 2 : x = \frac{1}{2} ln (2)

e^{x} = 2

Apply exponent rules

e^{x} = 2

Apply exponent rule:

a = a^{\frac{1}{2}}

2 = 2^{\frac{1}{2}}

e^{x} = 2^{\frac{1}{2}}

f (x) = g (x)

, then

ln (f (x)) = ln (g (x))

ln (e^{x}) = ln (2^{\frac{1}{2}})

Apply log rule:

ln (e^{a}) = a

ln (e^{x}) = x

x = ln (2^{\frac{1}{2}})

Apply log rule:

ln (x^{a}) = a \cdot ln (x)

ln (2^{\frac{1}{2}}) = \frac{1}{2} ln (2)

x = \frac{1}{2} ln (2)

x = \frac{1}{2} ln (2)

Solve

e^{x} = \frac{1}{2} : x = - \frac{1}{2} ln (2)

e^{x} = \frac{1}{2}

Apply exponent rules

e^{x} = \frac{1}{2}

Apply exponent rule:

\frac{1}{a ^{b}} = a^{- b}

\frac{1}{2} = 2^{- \frac{1}{2}}

e^{x} = 2^{- \frac{1}{2}}

Apply exponent rule:

2^{- \frac{1}{2}} = 2^{- \frac{1}{2}}

e^{x} = 2^{- \frac{1}{2}}

f (x) = g (x)

, then

ln (f (x)) = ln (g (x))

ln (e^{x}) = ln (2^{- \frac{1}{2}})

Apply log rule:

ln (e^{a}) = a

ln (e^{x}) = x

x = ln (2^{- \frac{1}{2}})

Apply log rule:

ln (x^{a}) = a \cdot ln (x)

ln (2^{- \frac{1}{2}}) = - \frac{1}{2} ln (2)

x = - \frac{1}{2} ln (2)

x = - \frac{1}{2} ln (2)

x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

Graph

Popular Examples

Frequently Asked Questions (FAQ)

What is the general solution for 64cosh^4(x)-64cosh^2(x)-9=0 ?
The general solution for 64cosh^4(x)-64cosh^2(x)-9=0 is x= 1/2 ln(2),x=-1/2 ln(2)