What is the general solution for sin(θ)=0.25 ?

The general solution for sin(θ)=0.25 is θ=0.25268…+2pin,θ=pi-0.25268…+2pin

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sin(θ)=0.25

sin (θ) = 0.25

θ = 0.25268 \dots + 2 πn, θ = π - 0.25268 \dots + 2 πn

Degrees

θ = 14.47751 \dots^{\circ} + 36 0^{\circ} n, θ = 165.52248 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = 0.25

Apply trig inverse properties

sin (θ) = 0.25

General solutions for

sin (θ) = 0.25

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (0.25) + 2 πn, θ = π - arcsin (0.25) + 2 πn

θ = arcsin (0.25) + 2 πn, θ = π - arcsin (0.25) + 2 πn

Show solutions in decimal form

θ = 0.25268 \dots + 2 πn, θ = π - 0.25268 \dots + 2 πn

3 0^{2} = 2 0^{2} + 1 8^{2} - 2 (20) (18) cos (A)

cos (x) = \frac{308}{1475}

tan (θ) = \frac{6}{3}

csc (θ) = - \frac{13}{5}

17 sin (θ + 61. 9^{\circ}) = k

What is the general solution for sin(θ)=0.25 ?
The general solution for sin(θ)=0.25 is θ=0.25268…+2pin,θ=pi-0.25268…+2pin