What is the general solution for 5+tan(θ)=4 ?

The general solution for 5+tan(θ)=4 is θ=(3pi)/4+pin

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5+tan(θ)=4

5 + tan (θ) = 4

θ = \frac{3 π}{4} + πn

Degrees

θ = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

5 + tan (θ) = 4

Move

5

to the right side

5 + tan (θ) = 4

Subtract

5

from both sides

5 + tan (θ) - 5 = 4 - 5

Simplify

tan (θ) = - 1

tan (θ) = - 1

General solutions for

tan (θ) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

arctan (e^{x}) = 0

cos (x) = 3 - cos (x)

4 sin^{2} (x) + 1 = 4 sin (x)

- 0.6 = sin (30 t)

1 = tan (\frac{π}{4} + x)

What is the general solution for 5+tan(θ)=4 ?
The general solution for 5+tan(θ)=4 is θ=(3pi)/4+pin