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Popular Trigonometry >

1sin(45)=2.42sin(r)

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Solution

1sin(45∘)=2.42sin(r)

Solution

r=0.29651…+360∘n,r=180∘−0.29651…+360∘n
+1
Radians
r=0.29651…+2πn,r=π−0.29651…+2πn
Solution steps
1⋅sin(45∘)=2.42sin(r)
sin(45∘)=22​​
sin(45∘)
Use the following trivial identity:sin(45∘)=22​​
sin(45∘)
sin(x) periodicity table with 360∘n cycle:
x030∘45∘60∘90∘120∘135∘150∘​sin(x)021​22​​23​​123​​22​​21​​x180∘210∘225∘240∘270∘300∘315∘330∘​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=22​​
=22​​
1⋅22​​=2.42sin(r)
Switch sides2.42sin(r)=1⋅22​​
Multiply both sides by 100
2.42sin(r)=1⋅22​​
To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere are 2digits to the right of the decimal point, therefore multiply by 1002.42sin(r)⋅100=1⋅22​​⋅100
Refine242sin(r)=502​
242sin(r)=502​
Divide both sides by 242
242sin(r)=502​
Divide both sides by 242242242sin(r)​=242502​​
Simplifysin(r)=121252​​
sin(r)=121252​​
Apply trig inverse properties
sin(r)=121252​​
General solutions for sin(r)=121252​​sin(x)=a⇒x=arcsin(a)+360∘n,x=180∘−arcsin(a)+360∘nr=arcsin(121252​​)+360∘n,r=180∘−arcsin(121252​​)+360∘n
r=arcsin(121252​​)+360∘n,r=180∘−arcsin(121252​​)+360∘n
Show solutions in decimal formr=0.29651…+360∘n,r=180∘−0.29651…+360∘n

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Frequently Asked Questions (FAQ)

  • What is the general solution for 1sin(45)=2.42sin(r) ?

    The general solution for 1sin(45)=2.42sin(r) is r=0.29651…+360n,r=180-0.29651…+360n
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