sec(θ)= 13/12

Lösung

sec (θ) = \frac{13}{12}

θ = 0.39479 \dots + 2 πn, θ = 2 π - 0.39479 \dots + 2 πn

Grad

θ = 22.61986 \dots^{\circ} + 36 0^{\circ} n, θ = 337.38013 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

sec (θ) = \frac{13}{12}

Wende die Eigenschaften der Trigonometrie an

sec (θ) = \frac{13}{12}

Allgemeine Lösung für

sec (θ) = \frac{13}{12}

sec (x) = a \Rightarrow x = arcsec (a) + 2 πn, x = 2 π - arcsec (a) + 2 πn

θ = arcsec (\frac{13}{12}) + 2 πn, θ = 2 π - arcsec (\frac{13}{12}) + 2 πn

θ = arcsec (\frac{13}{12}) + 2 πn, θ = 2 π - arcsec (\frac{13}{12}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.39479 \dots + 2 πn, θ = 2 π - 0.39479 \dots + 2 πn

sin (7 0^{\circ}) = 1.15 sin (x)

cos (θ) = - cos (2 θ)

3 (sin (x) - cos (x)) = 2 (sin (x) + cos (x))

so l v e f or θ, ma = t sin (θ) - m g

tan^{2} (x) + 3 = 3 sec (x)