What is the general solution for cot(θ-pi/2)=1.07,tan(θ) ?

The general solution for cot(θ-pi/2)=1.07,tan(θ) is No Solution for θ\in\mathbb{R}

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cot(θ-pi/2)=1.07,tan(θ)

cot (θ - \frac{π}{2}) = 1.07, tan (θ)

No Solution for θ \in R

Solution steps

cot (θ - \frac{π}{2}) = 1.07, tan (θ)

Apply trig inverse properties

cot (θ - \frac{π}{2}) = 1.07

General solutions for

cot (θ - \frac{π}{2}) = 1.07

cot (x) = a \Rightarrow x = arccot (a) + πn

θ - \frac{π}{2} = arccot (1.07) + πn

θ - \frac{π}{2} = arccot (1.07) + πn

Solve

θ - \frac{π}{2} = arccot (1.07) + πn : θ = arccot (1.07) + πn + \frac{π}{2}

θ - \frac{π}{2} = arccot (1.07) + πn

Move

\frac{π}{2}

to the right side

θ - \frac{π}{2} = arccot (1.07) + πn

Add

\frac{π}{2}

to both sides

θ - \frac{π}{2} + \frac{π}{2} = arccot (1.07) + πn + \frac{π}{2}

Simplify

θ = arccot (1.07) + πn + \frac{π}{2}

θ = arccot (1.07) + πn + \frac{π}{2}

θ = arccot (1.07) + πn + \frac{π}{2}

Solutions for the range

tan (θ)

No Solution for θ \in R

sin (b) = 0.4848

sin (2 θ) + 2 cos (θ) = 0

cos (θ) = \frac{13}{12}

3 tan^{2} (θ) + 3 tan (θ) = 0

cos (x) = sin^{2} (x) - 1

What is the general solution for cot(θ-pi/2)=1.07,tan(θ) ?
The general solution for cot(θ-pi/2)=1.07,tan(θ) is No Solution for θ\in\mathbb{R}