What is the general solution for cos(a)=(-sqrt(3))/2 ?

The general solution for cos(a)=(-sqrt(3))/2 is a=(5pi)/6+2pin,a=(7pi)/6+2pin

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cos(a)=(-sqrt(3))/2

cos (a) = \frac{- 3}{2}

a = \frac{5 π}{6} + 2 πn, a = \frac{7 π}{6} + 2 πn

Degrees

a = 15 0^{\circ} + 36 0^{\circ} n, a = 21 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (a) = \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

cos (a) = - \frac{3}{2}

General solutions for

cos (a) = - \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

a = \frac{5 π}{6} + 2 πn, a = \frac{7 π}{6} + 2 πn

a = \frac{5 π}{6} + 2 πn, a = \frac{7 π}{6} + 2 πn

2 cos (2 c) = \frac{( 0 ) - ( 0 )}{( π ) - ( - π )}

- 5 cos (2 θ) - 9 sin (θ) + 8 = - sin (θ)

3 + 3 cos (θ) = 3 + 3 sin (θ)

sinh (x) = \frac{4}{3}

x, f^{- 1} = arctan (x^{3} - 1)

What is the general solution for cos(a)=(-sqrt(3))/2 ?
The general solution for cos(a)=(-sqrt(3))/2 is a=(5pi)/6+2pin,a=(7pi)/6+2pin