What is the general solution for cos(x)= 2/(sqrt(13)) ?

The general solution for cos(x)= 2/(sqrt(13)) is x=0.98279…+2pin,x=2pi-0.98279…+2pin

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cos(x)= 2/(sqrt(13))

cos (x) = \frac{2}{13}

x = 0.98279 \dots + 2 πn, x = 2 π - 0.98279 \dots + 2 πn

Radians

x = 0.98279 \dots + 6.28318 \dots n, x = 5.30039 \dots + 6.28318 \dots n

Solution steps

cos (x) = \frac{2}{13}

Simplify

\frac{2}{13} : \frac{2 13}{13}

\frac{2}{13}

Multiply by the conjugate

\frac{13}{13}

= \frac{2 13}{13 13}

1313 = 13

1313

Apply radical rule:

a a = a

1313 = 13

= 13

= \frac{2 13}{13}

cos (x) = \frac{2 13}{13}

Apply trig inverse properties

cos (x) = \frac{2 13}{13}

General solutions for

cos (x) = \frac{2 13}{13}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{2 13}{13}) + 2 πn, x = 2 π - arccos (\frac{2 13}{13}) + 2 πn

x = arccos (\frac{2 13}{13}) + 2 πn, x = 2 π - arccos (\frac{2 13}{13}) + 2 πn

Show solutions in decimal form

x = 0.98279 \dots + 2 πn, x = 2 π - 0.98279 \dots + 2 πn

cos (θ) = sec (θ)

4.45 tan^{2} (θ) - 23 tan (θ) + 16.15 = 0

sin^{2} (x) = \frac{( 3 m - 2 )}{8}

arccos (x) = arcsin (\frac{1}{3}) + arccos (\frac{1}{4})

sin (2 x) = cos (4 0^{\circ})

What is the general solution for cos(x)= 2/(sqrt(13)) ?
The general solution for cos(x)= 2/(sqrt(13)) is x=0.98279…+2pin,x=2pi-0.98279…+2pin