What is the general solution for tan(x-10)=0 ?

The general solution for tan(x-10)=0 is x=180n+10

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tan(x-10)=0

tan (x - 1 0^{\circ}) = 0

x = 18 0^{\circ} n + 1 0^{\circ}

Radians

x = \frac{π}{18} + πn

Solution steps

tan (x - 1 0^{\circ}) = 0

General solutions for

tan (x - 1 0^{\circ}) = 0

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x - 1 0^{\circ} = 0 + 18 0^{\circ} n

x - 1 0^{\circ} = 0 + 18 0^{\circ} n

Solve

x - 1 0^{\circ} = 0 + 18 0^{\circ} n : x = 18 0^{\circ} n + 1 0^{\circ}

x - 1 0^{\circ} = 0 + 18 0^{\circ} n

0 + 18 0^{\circ} n = 18 0^{\circ} n

x - 1 0^{\circ} = 18 0^{\circ} n

Move

1 0^{\circ}

to the right side

x - 1 0^{\circ} = 18 0^{\circ} n

Add

1 0^{\circ}

to both sides

x - 1 0^{\circ} + 1 0^{\circ} = 18 0^{\circ} n + 1 0^{\circ}

Simplify

x = 18 0^{\circ} n + 1 0^{\circ}

x = 18 0^{\circ} n + 1 0^{\circ}

x = 18 0^{\circ} n + 1 0^{\circ}

cos^{2} (x) = 3 sin (x) cos (x)

cos (θ) - 3 cos (2 θ) = 0

sin^{2} (x) + 3 sin (x) = 4

sin (y) = \frac{50}{65.3}

0.26 = \frac{1 - sin ( x )}{1 + sin ( x )}

What is the general solution for tan(x-10)=0 ?
The general solution for tan(x-10)=0 is x=180n+10