What is the general solution for cos(x)=0.22 ?

The general solution for cos(x)=0.22 is x=1.34898…+2pin,x=2pi-1.34898…+2pin

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cos(x)=0.22

cos (x) = 0.22

x = 1.34898 \dots + 2 πn, x = 2 π - 1.34898 \dots + 2 πn

Degrees

x = 77.29096 \dots^{\circ} + 36 0^{\circ} n, x = 282.70903 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = 0.22

Apply trig inverse properties

cos (x) = 0.22

General solutions for

cos (x) = 0.22

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.22) + 2 πn, x = 2 π - arccos (0.22) + 2 πn

x = arccos (0.22) + 2 πn, x = 2 π - arccos (0.22) + 2 πn

Show solutions in decimal form

x = 1.34898 \dots + 2 πn, x = 2 π - 1.34898 \dots + 2 πn

What is the general solution for cos(x)=0.22 ?
The general solution for cos(x)=0.22 is x=1.34898…+2pin,x=2pi-1.34898…+2pin