What is the general solution for solvefor x,y=2arcsin(x-1) ?

The general solution for solvefor x,y=2arcsin(x-1) is x=sin(y/2)+1

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solvefor x,y=2arcsin(x-1)

solve for

x, y = 2 arcsin (x - 1)

x = sin (\frac{y}{2}) + 1

Solution steps

y = 2 arcsin (x - 1)

Switch sides

2 arcsin (x - 1) = y

Divide both sides by

2

2 arcsin (x - 1) = y

Divide both sides by

2

\frac{2 arcsin ( x - 1 )}{2} = \frac{y}{2}

Simplify

arcsin (x - 1) = \frac{y}{2}

arcsin (x - 1) = \frac{y}{2}

Apply trig inverse properties

arcsin (x - 1) = \frac{y}{2}

arcsin (x) = a \Rightarrow x = sin (a)

x - 1 = sin (\frac{y}{2})

x - 1 = sin (\frac{y}{2})

Solve

x - 1 = sin (\frac{y}{2}) : x = sin (\frac{y}{2}) + 1

x - 1 = sin (\frac{y}{2})

Move

1

to the right side

x - 1 = sin (\frac{y}{2})

Add

1

to both sides

x - 1 + 1 = sin (\frac{y}{2}) + 1

Simplify

x = sin (\frac{y}{2}) + 1

x = sin (\frac{y}{2}) + 1

x = sin (\frac{y}{2}) + 1

x, - 2 sin (x) - 1 = 0

sin (t) = \frac{1}{8}

sin (θ) - 0.2 \cdot cos (θ) = 0.48979

1 = 1 + 3 sin (3 θ)

cos (\frac{θ}{4}) = \frac{2}{2}

What is the general solution for solvefor x,y=2arcsin(x-1) ?
The general solution for solvefor x,y=2arcsin(x-1) is x=sin(y/2)+1