What is the general solution for 2cos(x)-4=-3 ?

The general solution for 2cos(x)-4=-3 is x= pi/3+2pin,x=(5pi)/3+2pin

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2cos(x)-4=-3

2 cos (x) - 4 = - 3

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Degrees

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

2 cos (x) - 4 = - 3

Move

4

to the right side

2 cos (x) - 4 = - 3

Add

4

to both sides

2 cos (x) - 4 + 4 = - 3 + 4

Simplify

2 cos (x) = 1

2 cos (x) = 1

Divide both sides by

2

2 cos (x) = 1

Divide both sides by

2

\frac{2 cos ( x )}{2} = \frac{1}{2}

Simplify

cos (x) = \frac{1}{2}

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

\frac{sin ( 2 x )}{sin ( \frac{7 π}{2} - x )} = 2

- 2 sec (θ) + 23 = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

cos (x + 1) = - \frac{2}{5}

4 cos (2 x) + 1 = 3

sinh^{2} (x) = 0

What is the general solution for 2cos(x)-4=-3 ?
The general solution for 2cos(x)-4=-3 is x= pi/3+2pin,x=(5pi)/3+2pin