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人気のある三角関数 >

sin(3x)=0,0<= x<2pi

解

sin (3 x) = 0, 0 \leq x < 2 π

解

x = 0, x = \frac{π}{3}, x = \frac{2 π}{3}, x = π, x = \frac{4 π}{3}, x = \frac{5 π}{3}

+1

度

x = 0^{\circ}, x = 6 0^{\circ}, x = 12 0^{\circ}, x = 18 0^{\circ}, x = 24 0^{\circ}, x = 30 0^{\circ}

解答ステップ

sin (3 x) = 0, 0 \leq x < 2 π

以下の一般解

sin (3 x) = 0

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

3 x = 0 + 2 πn, 3 x = π + 2 πn

3 x = 0 + 2 πn, 3 x = π + 2 πn

解く

3 x = 0 + 2 πn : x = \frac{2 πn}{3}

3 x = 0 + 2 πn

0 + 2 πn = 2 πn

3 x = 2 πn

以下で両辺を割る

3

3 x = 2 πn

以下で両辺を割る

3

\frac{3 x}{3} = \frac{2 πn}{3}

簡素化

x = \frac{2 πn}{3}

x = \frac{2 πn}{3}

解く

3 x = π + 2 πn : x = \frac{π}{3} + \frac{2 πn}{3}

3 x = π + 2 πn

以下で両辺を割る

3

3 x = π + 2 πn

以下で両辺を割る

3

\frac{3 x}{3} = \frac{π}{3} + \frac{2 πn}{3}

簡素化

x = \frac{π}{3} + \frac{2 πn}{3}

x = \frac{π}{3} + \frac{2 πn}{3}

x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}

範囲の解答

0 \leq x < 2 π

x = 0, x = \frac{π}{3}, x = \frac{2 π}{3}, x = π, x = \frac{4 π}{3}, x = \frac{5 π}{3}

グラフ

人気の例

sin(θ)=-1/5 ,pi<θ<(3pi)/2 ,cos(θ)

sin (θ) = - \frac{1}{5}, π < θ < \frac{3 π}{2}, cos (θ)

(sin(x))/(37)=(sin(30))/(30)

\frac{sin ( x )}{37} = \frac{sin ( 3 0 ^{\circ} )}{30}

solvefor t,x=arccos(1/(sqrt(1+t^2)))

so l v e f or t, x = arccos (\frac{1}{1 + t ^{2}})

(1-sin(x))(1+cos(x))=cos^2(x)

(1 - sin (x)) (1 + cos (x)) = cos^{2} (x)

2cos^2(x)+15sin(x)-15=0

2 cos^{2} (x) + 15 sin (x) - 15 = 0