What is the general solution for cos(x)= 1/2 ,0<= x<= 360 ?

The general solution for cos(x)= 1/2 ,0<= x<= 360 is x=60,x=300

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

cos(x)= 1/2 ,0<= x<= 360

cos (x) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

x = 6 0^{\circ}, x = 30 0^{\circ}

Radians

x = \frac{π}{3}, x = \frac{5 π}{3}

Solution steps

cos (x) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

General solutions for

cos (x) = \frac{1}{2}

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

Solutions for the range

0 \leq x \leq 36 0^{\circ}

x = 6 0^{\circ}, x = 30 0^{\circ}

4 + 4 sin (θ) = \frac{3}{1 - sin ( θ )}

x, z = arctan (x y)

(sin (x) - 5) (sin (x) - 1) = 0

sin (6 x) = \frac{1}{2}

0 = 9 cos (2 θ)

What is the general solution for cos(x)= 1/2 ,0<= x<= 360 ?
The general solution for cos(x)= 1/2 ,0<= x<= 360 is x=60,x=300