What is the general solution for cos(x)= 1/2 ,0<= x<= 360 ?

The general solution for cos(x)= 1/2 ,0<= x<= 360 is x=60,x=300

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cos(x)= 1/2 ,0<= x<= 360

cos (x) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

x = 6 0^{\circ}, x = 30 0^{\circ}

Radians

x = \frac{π}{3}, x = \frac{5 π}{3}

Solution steps

cos (x) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

General solutions for

cos (x) = \frac{1}{2}

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

Solutions for the range

0 \leq x \leq 36 0^{\circ}

x = 6 0^{\circ}, x = 30 0^{\circ}

- 44 sin (2 x) + 42 cos (2 x) = 0

cos^{2} (x) = cos (x) + 2

cos^{2} (x) = cos (x) - 1

4 + 4 sin (θ) = \frac{3}{1 - sin ( θ )}

sin^{2} (x) + cos^{4} (x) = n

What is the general solution for cos(x)= 1/2 ,0<= x<= 360 ?
The general solution for cos(x)= 1/2 ,0<= x<= 360 is x=60,x=300