What is the general solution for cos(2x+15)=sin(x/2-15) ?

The general solution for cos(2x+15)=sin(x/2-15) is x=(-180+4320n+1260)/(30),x=-(1260+4320n+180)/(18)

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cos(2x+15)=sin(x/2-15)

Solution

cos (2 x + 15) = sin (\frac{x}{2} - 1 5^{\circ})

Solution

x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}, x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

Radians

x = - 6 + \frac{\frac{7 π}{5}}{6} + \frac{\frac{24 π}{5}}{6} n, x = - 10 - \frac{7 π}{18} - \frac{24 π}{18} n

Solution steps

cos (2 x + 15) = sin (\frac{x}{2} - 1 5^{\circ})

Rewrite using trig identities

cos (2 x + 15) = sin (\frac{x}{2} - 1 5^{\circ})

Use the following identity:

cos (x) = sin (9 0^{\circ} - x)

cos (2 x + 15) = sin (9 0^{\circ} - (2 x + 15))

cos (2 x + 15) = sin (9 0^{\circ} - (2 x + 15))

Apply trig inverse properties

cos (2 x + 15) = sin (9 0^{\circ} - (2 x + 15))

sin (x) = sin (y) \Rightarrow x = y + 2 π n, x = π - y + 2 π n

\frac{x}{2} - 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n, \frac{x}{2} - 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n

\frac{x}{2} - 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n, \frac{x}{2} - 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n

\frac{x}{2} - 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n : x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}

\frac{x}{2} - 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n

Move

1 5^{\circ}

to the right side

\frac{x}{2} - 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n

Add

1 5^{\circ}

to both sides

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n + 1 5^{\circ}

Simplify

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ} = 9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n + 1 5^{\circ}

Simplify

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ} : \frac{x}{2}

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ}

Add similar elements:

- 1 5^{\circ} + 1 5^{\circ} = 0

= \frac{x}{2}

Simplify

9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n + 1 5^{\circ} : - 2 x - 15 + 36 0^{\circ} n + 10 5^{\circ}

9 0^{\circ} - (2 x + 15) + 36 0^{\circ} n + 1 5^{\circ}

Least Common Multiplier of

2, 12 : 12

2, 12

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

12 : 2 \cdot 2 \cdot 3

12

12

divides by

212 = 6 \cdot 2

= 2 \cdot 6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

12

= 2 \cdot 2 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 = 12

= 12

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

12

For

9 0^{\circ} :

multiply the denominator and numerator by

6

9 0^{\circ} = \frac{18 0 ^{\circ} 6}{2 \cdot 6} = 9 0^{\circ}

= 9 0^{\circ} + 1 5^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 6 + 18 0 ^{\circ}}{12}

Add similar elements:

108 0^{\circ} + 18 0^{\circ} = 126 0^{\circ}

= - (2 x + 15) + 36 0^{\circ} n + 10 5^{\circ}

- (2 x + 15) : - 2 x - 15

- (2 x + 15)

Distribute parentheses

= - (2 x) - (15)

Apply minus-plus rules

+ (- a) = - a

= - 2 x - 15

= - 2 x - 15 + 36 0^{\circ} n + 10 5^{\circ}

\frac{x}{2} = - 2 x - 15 + 36 0^{\circ} n + 10 5^{\circ}

\frac{x}{2} = - 2 x - 15 + 36 0^{\circ} n + 10 5^{\circ}

\frac{x}{2} = - 2 x - 15 + 36 0^{\circ} n + 10 5^{\circ}

Multiply both sides by

2

\frac{x}{2} = - 2 x - 15 + 36 0^{\circ} n + 10 5^{\circ}

Multiply both sides by

2

\frac{x}{2} \cdot 2 = - 2 x \cdot 2 - 15 \cdot 2 + 36 0^{\circ} n \cdot 2 + 10 5^{\circ} \cdot 2

Simplify

\frac{x}{2} \cdot 2 = - 2 x \cdot 2 - 15 \cdot 2 + 36 0^{\circ} n \cdot 2 + 10 5^{\circ} \cdot 2

Simplify

\frac{x}{2} \cdot 2 : x

\frac{x}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x \cdot 2}{2}

Cancel the common factor:

2

= x

Simplify

- 2 x \cdot 2 : - 4 x

- 2 x \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= - 4 x

Simplify

- 15 \cdot 2 : - 30

- 15 \cdot 2

Multiply the numbers:

15 \cdot 2 = 30

= - 30

Simplify

36 0^{\circ} n \cdot 2 : 72 0^{\circ} n

36 0^{\circ} n \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 72 0^{\circ} n

Simplify

10 5^{\circ} \cdot 2 : 21 0^{\circ}

10 5^{\circ} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 21 0^{\circ}

Multiply the numbers:

7 \cdot 2 = 14

= 21 0^{\circ}

Cancel the common factor:

2

= 21 0^{\circ}

x = - 4 x - 30 + 72 0^{\circ} n + 21 0^{\circ}

x = - 4 x - 30 + 72 0^{\circ} n + 21 0^{\circ}

x = - 4 x - 30 + 72 0^{\circ} n + 21 0^{\circ}

Move

4 x

to the left side

x = - 4 x - 30 + 72 0^{\circ} n + 21 0^{\circ}

Add

4 x

to both sides

x + 4 x = - 4 x - 30 + 72 0^{\circ} n + 21 0^{\circ} + 4 x

Simplify

5 x = - 30 + 72 0^{\circ} n + 21 0^{\circ}

5 x = - 30 + 72 0^{\circ} n + 21 0^{\circ}

Divide both sides by

5

5 x = - 30 + 72 0^{\circ} n + 21 0^{\circ}

Divide both sides by

5

\frac{5 x}{5} = - \frac{30}{5} + \frac{72 0 ^{\circ} n}{5} + \frac{21 0 ^{\circ}}{5}

Simplify

\frac{5 x}{5} = - \frac{30}{5} + \frac{72 0 ^{\circ} n}{5} + \frac{21 0 ^{\circ}}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

- \frac{30}{5} + \frac{72 0 ^{\circ} n}{5} + \frac{21 0 ^{\circ}}{5} : \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}

- \frac{30}{5} + \frac{72 0 ^{\circ} n}{5} + \frac{21 0 ^{\circ}}{5}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 30 + 72 0 ^{\circ} n + 21 0 ^{\circ}}{5}

Join

- 30 + 72 0^{\circ} n + 21 0^{\circ} : \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{6}

- 30 + 72 0^{\circ} n + 21 0^{\circ}

Convert element to fraction:

30 = \frac{30 \cdot 6}{6}, 72 0^{\circ} n = \frac{72 0 ^{\circ} n 6}{6}

= - \frac{30 \cdot 6}{6} + \frac{72 0 ^{\circ} n \cdot 6}{6} + 21 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 30 \cdot 6 + 72 0 ^{\circ} n \cdot 6 + 126 0 ^{\circ}}{6}

- 30 \cdot 6 + 72 0^{\circ} n \cdot 6 + 126 0^{\circ} = - 180 + 432 0^{\circ} n + 126 0^{\circ}

- 30 \cdot 6 + 72 0^{\circ} n \cdot 6 + 126 0^{\circ}

Multiply the numbers:

30 \cdot 6 = 180

= - 180 + 4 \cdot 108 0^{\circ} n + 126 0^{\circ}

Multiply the numbers:

4 \cdot 6 = 24

= - 180 + 432 0^{\circ} n + 126 0^{\circ}

= \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{6}

= \frac{\frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{6}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{6 \cdot 5}

Multiply the numbers:

6 \cdot 5 = 30

= \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}

x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}

x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}

x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}

\frac{x}{2} - 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n : x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

\frac{x}{2} - 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n

Move

1 5^{\circ}

to the right side

\frac{x}{2} - 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n

Add

1 5^{\circ}

to both sides

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n + 1 5^{\circ}

Simplify

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n + 1 5^{\circ}

Simplify

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ} : \frac{x}{2}

\frac{x}{2} - 1 5^{\circ} + 1 5^{\circ}

Add similar elements:

- 1 5^{\circ} + 1 5^{\circ} = 0

= \frac{x}{2}

Simplify

18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n + 1 5^{\circ} : 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

18 0^{\circ} - (9 0^{\circ} - (2 x + 15)) + 36 0^{\circ} n + 1 5^{\circ}

- (2 x + 15) : - 2 x - 15

- (2 x + 15)

Distribute parentheses

= - (2 x) - (15)

Apply minus-plus rules

+ (- a) = - a

= - 2 x - 15

= 18 0^{\circ} - (- 2 x + 9 0^{\circ} - 15) + 36 0^{\circ} n + 1 5^{\circ}

- (9 0^{\circ} - 2 x - 15) : - 9 0^{\circ} + 2 x + 15

- (9 0^{\circ} - 2 x - 15)

Distribute parentheses

= - (9 0^{\circ}) - (- 2 x) - (- 15)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - 9 0^{\circ} + 2 x + 15

= 18 0^{\circ} - 9 0^{\circ} + 2 x + 15 + 36 0^{\circ} n + 1 5^{\circ}

Simplify

18 0^{\circ} - 9 0^{\circ} + 2 x + 15 + 36 0^{\circ} n + 1 5^{\circ} : 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

18 0^{\circ} - 9 0^{\circ} + 2 x + 15 + 36 0^{\circ} n + 1 5^{\circ}

Group like terms

= 2 x + 18 0^{\circ} + 36 0^{\circ} n - 9 0^{\circ} + 1 5^{\circ} + 15

Combine the fractions

- 9 0^{\circ} + 1 5^{\circ} : - 7 5^{\circ}

- 9 0^{\circ} + 1 5^{\circ}

Least Common Multiplier of

2, 12 : 12

2, 12

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

12 : 2 \cdot 2 \cdot 3

12

12

divides by

212 = 6 \cdot 2

= 2 \cdot 6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

12

= 2 \cdot 2 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 = 12

= 12

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

12

For

9 0^{\circ} :

multiply the denominator and numerator by

6

9 0^{\circ} = \frac{18 0 ^{\circ} 6}{2 \cdot 6} = 9 0^{\circ}

= - 9 0^{\circ} + 1 5^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 18 0 ^{\circ} 6 + 18 0 ^{\circ}}{12}

Add similar elements:

- 108 0^{\circ} + 18 0^{\circ} = - 90 0^{\circ}

= \frac{- 90 0 ^{\circ}}{12}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - 7 5^{\circ}

= 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

= 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

\frac{x}{2} = 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

\frac{x}{2} = 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

\frac{x}{2} = 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

Multiply both sides by

2

\frac{x}{2} = 2 x + 18 0^{\circ} + 36 0^{\circ} n - 7 5^{\circ} + 15

Multiply both sides by

2

\frac{x}{2} \cdot 2 = 2 x \cdot 2 + 18 0^{\circ} 2 + 36 0^{\circ} n \cdot 2 - 7 5^{\circ} \cdot 2 + 15 \cdot 2

Simplify

\frac{x}{2} \cdot 2 = 2 x \cdot 2 + 18 0^{\circ} 2 + 36 0^{\circ} n \cdot 2 - 7 5^{\circ} \cdot 2 + 15 \cdot 2

Simplify

\frac{x}{2} \cdot 2 : x

\frac{x}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x \cdot 2}{2}

Cancel the common factor:

2

= x

Simplify

2 x \cdot 2 : 4 x

2 x \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 4 x

Simplify

18 0^{\circ} 2 : 36 0^{\circ}

18 0^{\circ} 2

Apply the commutative law:

18 0^{\circ} 2 = 36 0^{\circ}

36 0^{\circ}

Simplify

36 0^{\circ} n \cdot 2 : 72 0^{\circ} n

36 0^{\circ} n \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 72 0^{\circ} n

Simplify

- 7 5^{\circ} \cdot 2 : - 15 0^{\circ}

- 7 5^{\circ} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - 15 0^{\circ}

Multiply the numbers:

5 \cdot 2 = 10

= - 15 0^{\circ}

Cancel the common factor:

2

= - 15 0^{\circ}

Simplify

15 \cdot 2 : 30

15 \cdot 2

Multiply the numbers:

15 \cdot 2 = 30

= 30

x = 4 x + 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

x = 4 x + 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

x = 4 x + 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

Move

4 x

to the left side

x = 4 x + 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

Subtract

4 x

from both sides

x - 4 x = 4 x + 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30 - 4 x

Simplify

- 3 x = 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

- 3 x = 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

Divide both sides by

- 3

- 3 x = 36 0^{\circ} + 72 0^{\circ} n - 15 0^{\circ} + 30

Divide both sides by

- 3

\frac{- 3 x}{- 3} = \frac{36 0 ^{\circ}}{- 3} + \frac{72 0 ^{\circ} n}{- 3} - \frac{15 0 ^{\circ}}{- 3} + \frac{30}{- 3}

Simplify

\frac{- 3 x}{- 3} = \frac{36 0 ^{\circ}}{- 3} + \frac{72 0 ^{\circ} n}{- 3} - \frac{15 0 ^{\circ}}{- 3} + \frac{30}{- 3}

Simplify

\frac{- 3 x}{- 3} : x

\frac{- 3 x}{- 3}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

\frac{36 0 ^{\circ}}{- 3} + \frac{72 0 ^{\circ} n}{- 3} - \frac{15 0 ^{\circ}}{- 3} + \frac{30}{- 3} : - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

\frac{36 0 ^{\circ}}{- 3} + \frac{72 0 ^{\circ} n}{- 3} - \frac{15 0 ^{\circ}}{- 3} + \frac{30}{- 3}

Group like terms

= \frac{36 0 ^{\circ}}{- 3} + \frac{30}{- 3} + \frac{72 0 ^{\circ} n}{- 3} - \frac{15 0 ^{\circ}}{- 3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{36 0 ^{\circ} + 30 + 72 0 ^{\circ} n - 15 0 ^{\circ}}{- 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{36 0 ^{\circ} + 30 + 72 0 ^{\circ} n - 15 0 ^{\circ}}{3}

Join

36 0^{\circ} + 30 + 72 0^{\circ} n - 15 0^{\circ} : \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{6}

36 0^{\circ} + 30 + 72 0^{\circ} n - 15 0^{\circ}

Convert element to fraction:

36 0^{\circ} = 36 0^{\circ}, 30 = \frac{30 \cdot 6}{6}, 72 0^{\circ} n = \frac{72 0 ^{\circ} n 6}{6}

= 36 0^{\circ} + \frac{30 \cdot 6}{6} + \frac{72 0 ^{\circ} n \cdot 6}{6} - 15 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{36 0 ^{\circ} 6 + 30 \cdot 6 + 72 0 ^{\circ} n \cdot 6 - 90 0 ^{\circ}}{6}

36 0^{\circ} 6 + 30 \cdot 6 + 72 0^{\circ} n \cdot 6 - 90 0^{\circ} = 126 0^{\circ} + 432 0^{\circ} n + 180

36 0^{\circ} 6 + 30 \cdot 6 + 72 0^{\circ} n \cdot 6 - 90 0^{\circ}

Multiply the numbers:

2 \cdot 6 = 12

= 216 0^{\circ} + 30 \cdot 6 + 4 \cdot 108 0^{\circ} n - 90 0^{\circ}

Multiply the numbers:

30 \cdot 6 = 180

= 216 0^{\circ} + 180 + 4 \cdot 108 0^{\circ} n - 90 0^{\circ}

Multiply the numbers:

4 \cdot 6 = 24

= 216 0^{\circ} + 180 + 432 0^{\circ} n - 90 0^{\circ}

Group like terms

= 216 0^{\circ} - 90 0^{\circ} + 432 0^{\circ} n + 180

Add similar elements:

216 0^{\circ} - 90 0^{\circ} = 126 0^{\circ}

= 126 0^{\circ} + 432 0^{\circ} n + 180

= \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{6}

= - \frac{\frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{6}}{3}

Simplify

\frac{\frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{6}}{3} : \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

\frac{\frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{6}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{6 \cdot 3}

Multiply the numbers:

6 \cdot 3 = 18

= \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

= - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}, x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

x = \frac{- 180 + 432 0 ^{\circ} n + 126 0 ^{\circ}}{30}, x = - \frac{126 0 ^{\circ} + 432 0 ^{\circ} n + 180}{18}

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Frequently Asked Questions (FAQ)

What is the general solution for cos(2x+15)=sin(x/2-15) ?
The general solution for cos(2x+15)=sin(x/2-15) is x=(-180+4320n+1260)/(30),x=-(1260+4320n+180)/(18)