What is the value of (sin(60))/(1.5) ?

The value of (sin(60))/(1.5) is (sqrt(3))/3

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(sin(60))/(1.5)

\frac{sin ( 6 0 ^{\circ} )}{1.5}

\frac{3}{3}

Decimal

0.57735 \dots

Solution steps

\frac{sin ( 6 0 ^{\circ} )}{1.5}

= \frac{sin ( 6 0 ^{\circ} )}{\frac{3}{2}}

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{\frac{3}{2}}{\frac{3}{2}}

Simplify

\frac{\frac{3}{2}}{\frac{3}{2}} : \frac{3}{3}

\frac{\frac{3}{2}}{\frac{3}{2}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{3 \cdot 2}{2 \cdot 3}

Cancel the common factor:

2

= \frac{3}{3}

= \frac{3}{3}

What is the value of (sin(60))/(1.5) ?
The value of (sin(60))/(1.5) is (sqrt(3))/3