Is cos(B)csc(B)tan(B)=11 ?

The answer to whether cos(B)csc(B)tan(B)=11 is False

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prove cos(B)csc(B)tan(B)=11

prove

cos (B) csc (B) tan (B) = 11

False

Solution steps

cos (B) csc (B) tan (B) = 11

Show that the two sides are not equal

For

cos (B) csc (B) tan (B) = 11

plug in

B = 1

cos (1) csc (1) tan (1) = cos (1) csc (1) tan (1) (Decimal : 1)

cos (1) csc (1) tan (1)

Rewrite using trig identities:

csc (1) cos (1) = cot (1)

csc (1) cos (1)

Express with sin, cos

csc (1) cos (1)

Use the basic trigonometric identity:

csc (1) = \frac{1}{sin ( 1 )}

= \frac{1}{sin ( 1 )} cos (1)

Simplify

\frac{1}{sin ( 1 )} cos (1) : \frac{cos ( 1 )}{sin ( 1 )}

\frac{1}{sin ( 1 )} cos (1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 cos ( 1 )}{sin ( 1 )}

Multiply:

1 \cdot cos (1) = cos (1)

= \frac{cos ( 1 )}{sin ( 1 )}

= \frac{cos ( 1 )}{sin ( 1 )}

= \frac{cos ( 1 )}{sin ( 1 )}

Use the basic trigonometric identity:

\frac{cos ( 1 )}{sin ( 1 )} = cot (1)

= cot (1)

= cot (1)

= cos (1) csc (1) tan (1)

The two sides are not equal

\Rightarrow False

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