Is tan(8x)=(8tan(x))/(1-tan^2(x)) ?

The answer to whether tan(8x)=(8tan(x))/(1-tan^2(x)) is False

prove tan(8x)=(8tan(x))/(1-tan^2(x))

prove

tan (8 x) = \frac{8 tan ( x )}{1 - tan ^{2} ( x )}

False

Solution steps

tan (8 x) = \frac{8 tan ( x )}{1 - tan ^{2} ( x )}

Show that the two sides are not equal

For

tan (8 x) = \frac{8 tan ( x )}{1 - tan ^{2} ( x )}

plug in

x = 1

tan (8 \cdot 1) = - 6.79971 \dots

tan (8 \cdot 1)

Refine to a decimal form

= - 6.79971 \dots

\frac{8 tan ( 1 )}{1 - tan ^{2} ( 1 )} = - 8.74015 \dots

\frac{8 tan ( 1 )}{1 - tan ^{2} ( 1 )}

Refine to a decimal form

= - 8.74015 \dots

The two sides are not equal

\Rightarrow False

p ro v e tan (- a) = \frac{cos ( \frac{π}{2} + a )}{cos ( a )}

p ro v e sin (θ) - \frac{1}{sin ( θ )} = cos (θ)

p ro v e cos^{8} (x) = sin^{7} (x) cos^{1} (x)

p ro v e (cot (x) + 1)^{2} - 2 cot (x) = csc^{2} (x)

p ro v e cos (θ) = \frac{1}{3}

Is tan(8x)=(8tan(x))/(1-tan^2(x)) ?
The answer to whether tan(8x)=(8tan(x))/(1-tan^2(x)) is False