Is cot(x)+tan(x)=sec(csc(x)) ?

The answer to whether cot(x)+tan(x)=sec(csc(x)) is False

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prove cot(x)+tan(x)=sec(csc(x))

prove

cot (x) + tan (x) = sec (csc (x))

False

Solution steps

cot (x) + tan (x) = sec (csc (x))

Show that the two sides are not equal

For

cot (x) + tan (x) = sec (csc (x))

plug in

x = 1

cot (1) + tan (1) = 2.19950 \dots

cot (1) + tan (1)

Refine to a decimal form

= 2.19950 \dots

sec (csc (1)) = 2.67989 \dots

sec (csc (1))

Refine to a decimal form

= 2.67989 \dots

The two sides are not equal

\Rightarrow False

p ro v e cos (\frac{1}{3} π) = cos (- \frac{1}{3} π)

p ro v e (cot (x) + tan (x)) cos (x) = csc (x)

p ro v e cos (- \frac{5 π}{4}) = cos (\frac{3 π}{4})

p ro v e cos^{2} (2 x) + 1 + sin (2) = 2

p ro v e sin (3 x) = 2 \cdot sin (\frac{3 x}{2}) \cdot cos (\frac{3 x}{2})

Is cot(x)+tan(x)=sec(csc(x)) ?
The answer to whether cot(x)+tan(x)=sec(csc(x)) is False