Is sec(x)-sin(x)=cot(x)cos(x) ?

The answer to whether sec(x)-sin(x)=cot(x)cos(x) is False

prove sec(x)-sin(x)=cot(x)cos(x)

prove

sec (x) - sin (x) = cot (x) cos (x)

False

Solution steps

sec (x) - sin (x) = cot (x) cos (x)

Show that the two sides are not equal

For

sec (x) - sin (x) = cot (x) cos (x)

plug in

x = 1

sec (1) - sin (1) = 1.00934 \dots

sec (1) - sin (1)

Refine to a decimal form

= 1.00934 \dots

cot (1) cos (1) = 0.34692 \dots

cot (1) cos (1)

Refine to a decimal form

= 0.34692 \dots

The two sides are not equal

\Rightarrow False

p ro v e \frac{csc ( A )}{csc ( A ) - sin ( A )} = sec^{2} (A)

p ro v e csc^{4} (x) (cot^{2} (x)) = csc^{4} (x)

p ro v e \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 1 = sec^{2} (x)

p ro v e cos^{2} (x) tan^{2} (2 x) = sin^{2} (x)

p ro v e \frac{sin ( 2 x )}{2} = \frac{tan ( x )}{1 + tan ^{2} ( x )}

Is sec(x)-sin(x)=cot(x)cos(x) ?
The answer to whether sec(x)-sin(x)=cot(x)cos(x) is False