Is cos^2(x)tan^2(2x)=sin^2(x) ?

The answer to whether cos^2(x)tan^2(2x)=sin^2(x) is False

prove cos^2(x)tan^2(2x)=sin^2(x)

prove

cos^{2} (x) tan^{2} (2 x) = sin^{2} (x)

False

Solution steps

cos^{2} (x) tan^{2} (2 x) = sin^{2} (x)

Show that the two sides are not equal

For

cos^{2} (x) tan^{2} (2 x) = sin^{2} (x)

plug in

x = 1

cos^{2} (1) tan^{2} (2 \cdot 1) = 1.39377 \dots

cos^{2} (1) tan^{2} (2 \cdot 1)

Refine to a decimal form

= 1.39377 \dots

sin^{2} (1) = 0.70807 \dots

sin^{2} (1)

Refine to a decimal form

= 0.70807 \dots

The two sides are not equal

\Rightarrow False

p ro v e \frac{sin ( 2 x )}{2} = \frac{tan ( x )}{1 + tan ^{2} ( x )}

p ro v e csc (\frac{π}{12}) = sec (\frac{5 π}{12})

p ro v e 1 - \frac{cot ^{2} ( θ )}{csc ^{2} ( θ )} = sin^{2} (θ)

p ro v e csc^{2} (t) tan^{2} (t) - 1 = tan^{2} (t)

p ro v e \frac{1}{2} cos (x) = \frac{cos ( x )}{2}

Is cos^2(x)tan^2(2x)=sin^2(x) ?
The answer to whether cos^2(x)tan^2(2x)=sin^2(x) is False