Is (cot(x))/(tan(x)sec(x))=csc(x)-1 ?

The answer to whether (cot(x))/(tan(x)sec(x))=csc(x)-1 is False

prove (cot(x))/(tan(x)sec(x))=csc(x)-1

prove

\frac{cot ( x )}{tan ( x ) sec ( x )} = csc (x) - 1

False

Solution steps

\frac{cot ( x )}{tan ( x ) sec ( x )} = csc (x) - 1

Show that the two sides are not equal

For

\frac{cot ( x )}{tan ( x ) sec ( x )} = csc (x) - 1

plug in

x = 1

\frac{cot ( 1 )}{tan ( 1 ) sec ( 1 )} = 0.22275 \dots

\frac{cot ( 1 )}{tan ( 1 ) sec ( 1 )}

Refine to a decimal form

= 0.22275 \dots

csc (1) - 1 = 0.18839 \dots

csc (1) - 1

Refine to a decimal form

= 0.18839 \dots

The two sides are not equal

\Rightarrow False

p ro v e cos (\frac{π}{2} - x) cot (x) = cos (x)

p ro v e 2 sin (9 π - x) = 2 sin (x)

p ro v e \frac{sec ( x )}{csc ^{2} ( x )} = sec (x) - cos (x)

p ro v e (1 - cos (x)) = cos (x) - 1

p ro v e cos^{2} (x) = 1 + cos (2 x)

Is (cot(x))/(tan(x)sec(x))=csc(x)-1 ?
The answer to whether (cot(x))/(tan(x)sec(x))=csc(x)-1 is False