beweisen 1=sec^2(θ)-tan^2(θ)

Lösung

beweisen

1 = sec^{2} (θ) - tan^{2} (θ)

Wahr

Schritte zur Lösung

1 = sec^{2} (θ) - tan^{2} (θ)

Verwende die Pythagoreische Identität:

tan^{2} (x) + 1 = sec^{2} (x)

1 = sec^{2} (x) - tan^{2} (x)

\Rightarrow Wahr

p ro v e tan^{8} (x) = tan^{6} (x) sec^{2} (x) - tan^{6} (x)

p ro v e 2 (sin (2 y) cos (2 y)) = sin (4 y)

p ro v e \frac{( tan ^{2} ( t ) )}{sec ( t )} = sec (t) - cos (t)

p ro v e - sin (- 1) = sin (1)

p ro v e sin^{2} (y) cos^{2} (y) = \frac{1 - cos ( 4 x )}{8}