sec(t)=sqrt(2)

Lösung

sec (t) = 2

t = \frac{π}{4} + 2 πn, t = \frac{7 π}{4} + 2 πn

Grad

t = 4 5^{\circ} + 36 0^{\circ} n, t = 31 5^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

sec (t) = 2

Allgemeine Lösung für

sec (t) = 2

sec (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

t = \frac{π}{4} + 2 πn, t = \frac{7 π}{4} + 2 πn

t = \frac{π}{4} + 2 πn, t = \frac{7 π}{4} + 2 πn

tan (x + 2) = cot (4 x + 28)

4 cos^{2} (x) - 4 = 0

2 tan (x) + 5 = 3

3 sin (x) - 2 cos (x) = 1

3 tan^{2} (x) + 10 tan (x) + 7 = 0