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人気のある三角関数 >

4sec^2(x)+2tan^2(x)-6=0

解

4 sec^{2} (x) + 2 tan^{2} (x) - 6 = 0

解

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

+1

度

x = 3 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n, x = 21 0^{\circ} + 36 0^{\circ} n

解答ステップ

4 sec^{2} (x) + 2 tan^{2} (x) - 6 = 0

三角関数の公式を使用して書き換える

- 6 + 2 tan^{2} (x) + 4 sec^{2} (x)

ピタゴラスの公式を使用する:

tan^{2} (x) + 1 = sec^{2} (x)

tan^{2} (x) = sec^{2} (x) - 1

= - 6 + 2 (sec^{2} (x) - 1) + 4 sec^{2} (x)

簡素化

- 6 + 2 (sec^{2} (x) - 1) + 4 sec^{2} (x) : 6 sec^{2} (x) - 8

- 6 + 2 (sec^{2} (x) - 1) + 4 sec^{2} (x)

拡張

2 (sec^{2} (x) - 1) : 2 sec^{2} (x) - 2

2 (sec^{2} (x) - 1)

分配法則を適用する:

a (b - c) = ab - a c

a = 2, b = sec^{2} (x), c = 1

= 2 sec^{2} (x) - 2 \cdot 1

数を乗じる:

2 \cdot 1 = 2

= 2 sec^{2} (x) - 2

= - 6 + 2 sec^{2} (x) - 2 + 4 sec^{2} (x)

簡素化

- 6 + 2 sec^{2} (x) - 2 + 4 sec^{2} (x) : 6 sec^{2} (x) - 8

- 6 + 2 sec^{2} (x) - 2 + 4 sec^{2} (x)

条件のようなグループ

= 2 sec^{2} (x) + 4 sec^{2} (x) - 6 - 2

類似した元を足す:

2 sec^{2} (x) + 4 sec^{2} (x) = 6 sec^{2} (x)

= 6 sec^{2} (x) - 6 - 2

数を引く:

- 6 - 2 = - 8

= 6 sec^{2} (x) - 8

= 6 sec^{2} (x) - 8

= 6 sec^{2} (x) - 8

- 8 + 6 sec^{2} (x) = 0

置換で解く

- 8 + 6 sec^{2} (x) = 0

仮定:

sec (x) = u

- 8 + 6 u^{2} = 0

- 8 + 6 u^{2} = 0 : u = \frac{2 3}{3}, u = - \frac{2 3}{3}

- 8 + 6 u^{2} = 0

8

を右側に移動します

- 8 + 6 u^{2} = 0

両辺に

8

を足す

- 8 + 6 u^{2} + 8 = 0 + 8

簡素化

6 u^{2} = 8

6 u^{2} = 8

以下で両辺を割る

6

6 u^{2} = 8

以下で両辺を割る

6

\frac{6 u ^{2}}{6} = \frac{8}{6}

簡素化

u^{2} = \frac{4}{3}

u^{2} = \frac{4}{3}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{4}{3}, u = - \frac{4}{3}

\frac{4}{3} = \frac{2 3}{3}

\frac{4}{3}

累乗根の規則を適用する:

, 以下を想定

a \geq 0, b \geq 0

= \frac{4}{3}

4 = 2

4

数を因数に分解する:

4 = 2^{2}

= 2^{2}

累乗根の規則を適用する:

2^{2} = 2

= 2

= \frac{2}{3}

有理化する

\frac{2}{3} : \frac{2 3}{3}

\frac{2}{3}

共役で乗じる

\frac{3}{3}

= \frac{2 3}{3 3}

33 = 3

33

累乗根の規則を適用する:

a a = a

33 = 3

= 3

= \frac{2 3}{3}

= \frac{2 3}{3}

- \frac{4}{3} = - \frac{2 3}{3}

- \frac{4}{3}

簡素化

\frac{4}{3} : \frac{2}{3}

\frac{4}{3}

累乗根の規則を適用する:

, 以下を想定

a \geq 0, b \geq 0

= \frac{4}{3}

4 = 2

4

数を因数に分解する:

4 = 2^{2}

= 2^{2}

累乗根の規則を適用する:

2^{2} = 2

= 2

= \frac{2}{3}

= - \frac{2}{3}

有理化する

- \frac{2}{3} : - \frac{2 3}{3}

- \frac{2}{3}

共役で乗じる

\frac{3}{3}

= - \frac{2 3}{3 3}

33 = 3

33

累乗根の規則を適用する:

a a = a

33 = 3

= 3

= - \frac{2 3}{3}

= - \frac{2 3}{3}

u = \frac{2 3}{3}, u = - \frac{2 3}{3}

代用を戻す

u = sec (x)

sec (x) = \frac{2 3}{3}, sec (x) = - \frac{2 3}{3}

sec (x) = \frac{2 3}{3}, sec (x) = - \frac{2 3}{3}

sec (x) = \frac{2 3}{3} : x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sec (x) = \frac{2 3}{3}

以下の一般解

sec (x) = \frac{2 3}{3}

sec (x)

2 πn

循環を含む周期性テーブル :

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sec (x) = - \frac{2 3}{3} : x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

sec (x) = - \frac{2 3}{3}

以下の一般解

sec (x) = - \frac{2 3}{3}

sec (x)

2 πn

循環を含む周期性テーブル :

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

すべての解を組み合わせる

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

グラフ

人気の例

2tan(θ)cos^2(θ)=1

4cos^2(θ)-4cos(θ)+1=0