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Popular Trigonometry >

15sin(x)+7=sin(x)

  • Pre Algebra
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Solution

15sin(x)+7=sin(x)

Solution

x=67π​+2πn,x=611π​+2πn
+1
Degrees
x=210∘+360∘n,x=330∘+360∘n
Solution steps
15sin(x)+7=sin(x)
Solve by substitution
15sin(x)+7=sin(x)
Let: sin(x)=u15u+7=u
15u+7=u:u=−21​
15u+7=u
Move 7to the right side
15u+7=u
Subtract 7 from both sides15u+7−7=u−7
Simplify15u=u−7
15u=u−7
Move uto the left side
15u=u−7
Subtract u from both sides15u−u=u−7−u
Simplify14u=−7
14u=−7
Divide both sides by 14
14u=−7
Divide both sides by 141414u​=14−7​
Simplify
1414u​=14−7​
Simplify 1414u​:u
1414u​
Divide the numbers: 1414​=1=u
Simplify 14−7​:−21​
14−7​
Apply the fraction rule: b−a​=−ba​=−147​
Cancel the common factor: 7=−21​
u=−21​
u=−21​
u=−21​
Substitute back u=sin(x)sin(x)=−21​
sin(x)=−21​
sin(x)=−21​:x=67π​+2πn,x=611π​+2πn
sin(x)=−21​
General solutions for sin(x)=−21​
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
x=67π​+2πn,x=611π​+2πn
x=67π​+2πn,x=611π​+2πn
Combine all the solutionsx=67π​+2πn,x=611π​+2πn

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Popular Examples

3sin^2(x)+2sin(x)-1=03sin2(x)+2sin(x)−1=02cos(θ)=sqrt(3)2cos(θ)=3​-7sqrt(3)tan(θ)+2=9−73​tan(θ)+2=9tan^2(x)+2sec(x)=-1tan2(x)+2sec(x)=−12cos^2(θ)+3cos(θ)+1=02cos2(θ)+3cos(θ)+1=0

Frequently Asked Questions (FAQ)

  • What is the general solution for 15sin(x)+7=sin(x) ?

    The general solution for 15sin(x)+7=sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin
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