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受欢迎的三角函数 >

solvefor x,z=arctan(y/x)

解答

求解

x, z = arctan (\frac{y}{x})

解答

x = \frac{y}{tan ( z )}

求解步骤

z = arctan (\frac{y}{x})

交换两边

arctan (\frac{y}{x}) = z

使用反三角函数性质

arctan (\frac{y}{x}) = z

arctan (x) = a \Rightarrow x = tan (a)

\frac{y}{x} = tan (z)

\frac{y}{x} = tan (z)

解

\frac{y}{x} = tan (z) : x = \frac{y}{tan ( z )}; z \neq = πn

\frac{y}{x} = tan (z)

在两边乘以

x

\frac{y}{x} = tan (z)

在两边乘以

x

\frac{y}{x} x = tan (z) x

化简

y = tan (z) x

y = tan (z) x

交换两边

tan (z) x = y

两边除以

tan (z); z \neq = πn

tan (z) x = y

两边除以

tan (z); z \neq = πn

\frac{tan ( z ) x}{tan ( z )} = \frac{y}{tan ( z )}; z \neq = πn

化简

x = \frac{y}{tan ( z )}; z \neq = πn

x = \frac{y}{tan ( z )}; z \neq = πn

x = \frac{y}{tan ( z )}

作图

流行的例子

4sin^2(x)=2cos(x)+1

4 sin^{2} (x) = 2 cos (x) + 1

sin^2(x)=2+2cos(x)

sin^{2} (x) = 2 + 2 cos (x)

cos^2(2x+pi/6)= 1/2

cos^{2} (2 x + \frac{π}{6}) = \frac{1}{2}

cos(5x)=1,0<= x<= 2pi

cos (5 x) = 1, 0 \leq x \leq 2 π

sec(2θ)=2,0<θ< pi/2

sec (2 θ) = 2, 0 < θ < \frac{π}{2}