What is the derivative of \sqrt[3]{x}-1 ?

The derivative of \sqrt[3]{x}-1 is 1/(3x^{2/3)}

What is the first derivative of \sqrt[3]{x}-1 ?

The first derivative of \sqrt[3]{x}-1 is 1/(3x^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative

\frac{1}{3 x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (3 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (1) = 0

= \frac{1}{3 x ^{\frac{2}{3}}} - 0

Simplify

= \frac{1}{3 x ^{\frac{2}{3}}}

What is the derivative of \sqrt[3]{x}-1 ?
The derivative of \sqrt[3]{x}-1 is 1/(3x^{2/3)}
What is the first derivative of \sqrt[3]{x}-1 ?
The first derivative of \sqrt[3]{x}-1 is 1/(3x^{2/3)}