What is the derivative of y=sin(tan(2x)) ?

The derivative of y=sin(tan(2x)) is cos(tan(2x))sec^2(2x)*2

What is the first derivative of y=sin(tan(2x)) ?

The first derivative of y=sin(tan(2x)) is cos(tan(2x))sec^2(2x)*2

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derivative of

y = sin (tan (2 x))

cos (tan (2 x)) sec^{2} (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sin (tan (2 x)))

Apply the chain rule:

cos (tan (2 x)) \frac{d}{d x} (tan (2 x))

= cos (tan (2 x)) \frac{d}{d x} (tan (2 x))

\frac{d}{d x} (tan (2 x)) = sec^{2} (2 x) \cdot 2

= cos (tan (2 x)) sec^{2} (2 x) \cdot 2

- 2 x + 5

(- 43, 4)

y = 3

y = sin (x) cos (x)

f (x) = \frac{3}{4} x^{4} - \frac{4}{3} x^{3} + \frac{5}{2}

What is the derivative of y=sin(tan(2x)) ?
The derivative of y=sin(tan(2x)) is cos(tan(2x))sec^2(2x)*2
What is the first derivative of y=sin(tan(2x)) ?
The first derivative of y=sin(tan(2x)) is cos(tan(2x))sec^2(2x)*2