What is the derivative of f(x)=4^x ?

The derivative of f(x)=4^x is ln(2)*2^{2x+1}

What is the first derivative of f(x)=4^x ?

The first derivative of f(x)=4^x is ln(2)*2^{2x+1}

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derivative of

f (x) = 4^{x}

ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{x} ln (4)

Simplify

4^{x} ln (4) : ln (2) \cdot 2^{2 x + 1}

= ln (2) \cdot 2^{2 x + 1}

x - y = - 2

f (x) = x^{2} + 3

x^{2} e^{- x}

f (m) = \frac{1}{lo g _{3} ( m )}

f (x) = 5 x

What is the derivative of f(x)=4^x ?
The derivative of f(x)=4^x is ln(2)*2^{2x+1}
What is the first derivative of f(x)=4^x ?
The first derivative of f(x)=4^x is ln(2)*2^{2x+1}