What is the derivative of f(x)=x^2+3 ?

The derivative of f(x)=x^2+3 is 2x

What is the first derivative of f(x)=x^2+3 ?

The first derivative of f(x)=x^2+3 is 2x

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derivative of

f (x) = x^{2} + 3

2 x

Solution steps

\frac{d}{d x} (x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= 2 x + 0

Simplify

= 2 x

x^{2} e^{- x}

f (m) = \frac{1}{lo g _{3} ( m )}

f (x) = 5 x

f (x) = \frac{1}{2 x}

(1, 0)

What is the derivative of f(x)=x^2+3 ?
The derivative of f(x)=x^2+3 is 2x
What is the first derivative of f(x)=x^2+3 ?
The first derivative of f(x)=x^2+3 is 2x