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Popular >

distance (-2,3),(4,-1)

Solution

distance

(- 2, 3), (4, - 1)

Solution

213

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 3)

and

(4, - 1)

is

= (4 - (- 2))^{2} + (- 1 - 3)^{2}

Simplify

= 213

Popular Examples

midpoint (-1,-1),(1,2)midpoint

(- 1, - 1), (1, 2)

derivative of f(x)=cos(80)derivative of

f (x) = cos (8 0^{\circ})

tangent of f(x)=sqrt(x^2+18x+86)tangent of

f (x) = x^{2} + 18 x + 86

derivative of f(x)=-4x^3-cos(x)+2x derivative of

f (x) = - 4 x^{3} - cos (x) + 2 x

tangent of y=x^3 tangent of

y = x^{3}

Frequently Asked Questions (FAQ)

What is the distance (-2,3),(4,-1) ?
The distance (-2,3),(4,-1) is 2sqrt(13)