What is the derivative of f(x)=-4x^3-cos(x)+2x ?

The derivative of f(x)=-4x^3-cos(x)+2x is -12x^2+sin(x)+2

What is the first derivative of f(x)=-4x^3-cos(x)+2x ?

The first derivative of f(x)=-4x^3-cos(x)+2x is -12x^2+sin(x)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative

- 12 x^{2} + sin (x) + 2

Solution steps

\frac{d}{d x} (- 4 x^{3} - cos (x) + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (cos (x)) + \frac{d}{d x} (2 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (2 x) = 2

= - 12 x^{2} - (- sin (x)) + 2

Simplify

= - 12 x^{2} + sin (x) + 2

What is the derivative of f(x)=-4x^3-cos(x)+2x ?
The derivative of f(x)=-4x^3-cos(x)+2x is -12x^2+sin(x)+2
What is the first derivative of f(x)=-4x^3-cos(x)+2x ?
The first derivative of f(x)=-4x^3-cos(x)+2x is -12x^2+sin(x)+2