What is the derivative of f(x)=sqrt(x+9) ?

The derivative of f(x)=sqrt(x+9) is 1/(2sqrt(x+9))

What is the first derivative of f(x)=sqrt(x+9) ?

The first derivative of f(x)=sqrt(x+9) is 1/(2sqrt(x+9))

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derivative of

f (x) = x + 9

\frac{1}{2 x + 9}

Solution steps

\frac{d}{d x} (x + 9)

Apply the chain rule:

\frac{1}{2 x + 9} \frac{d}{d x} (x + 9)

= \frac{1}{2 x + 9} \frac{d}{d x} (x + 9)

\frac{d}{d x} (x + 9) = 1

= \frac{1}{2 x + 9} \cdot 1

Simplify

= \frac{1}{2 x + 9}

y = x^{3}

(- \frac{9 3}{2}, \frac{9}{2})

x 1 - x^{2}

y = 2 x + 1

(3.2, 2.5), (1.6, - 4.5)

What is the derivative of f(x)=sqrt(x+9) ?
The derivative of f(x)=sqrt(x+9) is 1/(2sqrt(x+9))
What is the first derivative of f(x)=sqrt(x+9) ?
The first derivative of f(x)=sqrt(x+9) is 1/(2sqrt(x+9))