{
"query": {
"display": "derivative of $$f\\left(x\\right)=\\sqrt{x+9}$$",
"symbolab_question": "PRE_CALC#derivative f(x)=\\sqrt{x+9}"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "\\frac{1}{2\\sqrt{x+9}}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\sqrt{x+9}\\right)=\\frac{1}{2\\sqrt{x+9}}$$",
"input": "\\frac{d}{dx}\\left(\\sqrt{x+9}\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}\\frac{1}{2\\sqrt{x+9}}\\frac{d}{dx}\\left(x+9\\right)$$",
"input": "\\frac{d}{dx}\\left(\\sqrt{x+9}\\right)",
"result": "=\\frac{1}{2\\sqrt{x+9}}\\frac{d}{dx}\\left(x+9\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=\\sqrt{u},\\:\\:u=x+9$$"
],
"result": "=\\frac{d}{du}\\left(\\sqrt{u}\\right)\\frac{d}{dx}\\left(x+9\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(\\sqrt{u}\\right)=\\frac{1}{2\\sqrt{u}}$$",
"input": "\\frac{d}{du}\\left(\\sqrt{u}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=\\frac{d}{du}\\left(u^{\\frac{1}{2}}\\right)",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=\\frac{1}{2}u^{\\frac{1}{2}-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{2}u^{\\frac{1}{2}-1}:{\\quad}\\frac{1}{2\\sqrt{u}}$$",
"input": "\\frac{1}{2}u^{\\frac{1}{2}-1}",
"result": "=\\frac{1}{2\\sqrt{u}}",
"steps": [
{
"type": "interim",
"title": "$$u^{\\frac{1}{2}-1}=u^{-\\frac{1}{2}}$$",
"input": "u^{\\frac{1}{2}-1}",
"steps": [
{
"type": "interim",
"title": "Join $$\\frac{1}{2}-1:{\\quad}-\\frac{1}{2}$$",
"input": "\\frac{1}{2}-1",
"result": "=u^{-\\frac{1}{2}}",
"steps": [
{
"type": "step",
"primary": "Convert element to fraction: $$1=\\frac{1\\cdot\\:2}{2}$$",
"result": "=-\\frac{1\\cdot\\:2}{2}+\\frac{1}{2}"
},
{
"type": "step",
"primary": "Since the denominators are equal, combine the fractions: $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{-1\\cdot\\:2+1}{2}"
},
{
"type": "interim",
"title": "$$-1\\cdot\\:2+1=-1$$",
"input": "-1\\cdot\\:2+1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:2=2$$",
"result": "=-2+1"
},
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-2+1=-1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s731snK5z/nd3Sq/6JpCqiX1XTSum/z5kLpMzXS1UJIew02FKSBoQo9V3G05AlnWtTyCE30rzMlUAIVDyhseMBropKGn5MuXZnb2ZCo/hVsBU="
}
},
{
"type": "step",
"result": "=\\frac{-1}{2}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Algebraic Manipulation Join Concise Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7VcI2MpaClJgyGWg1EkySKe0se7vRyav6BwUCJZptwG3MwViaLUXkeD+JukROhWdjMvOxDqXzE3/CFO0TFmffHAH2kDe5DGYTz3TrPquGdIhyukSOA/1RgMKO0TMhInPOMabdUggEogUL9RT7PNKh0VQW3Chm7McvYpuS87Y5EFs="
}
},
{
"type": "step",
"result": "=\\frac{1}{2}u^{-\\frac{1}{2}}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-b}=\\frac{1}{a^b}$$",
"secondary": [
"$$u^{-\\frac{1}{2}}=\\frac{1}{\\sqrt{u}}$$"
],
"result": "=\\frac{1}{2}\\cdot\\:\\frac{1}{\\sqrt{u}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{1\\cdot\\:1}{2\\sqrt{u}}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:1=1$$",
"result": "=\\frac{1}{2\\sqrt{u}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7JOPQ2g2GS9EQptV8nckZSrH6E/qPf7AlxQDX8MXU5OsAlilG71elit3w1IBbYN0P8rEus7TgCihQBF5omOFkJv2RkT96g5Q5jVbn5fyeQzwB9pA3uQxmE8906z6rhnSIHimBRYRqHSWeJkuUPhfTC1O468YRFxaQeTFqgRqR2rvsVWktCxa7XSYzIK90x3+aTk5AXTHU+C+TrGKWzqT97A=="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{1}{2\\sqrt{u}}\\frac{d}{dx}\\left(x+9\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=x+9$$",
"result": "=\\frac{1}{2\\sqrt{x+9}}\\frac{d}{dx}\\left(x+9\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYjasHTJ4Bo7yMP4qgzIlGERjwORqcQYfkxyrORpuTL6OdLl7DeVd7l7l/uUT/v1GhNJLZOXSTCXkMFKW90A2Pi/484O9NJ/PDg7/ATYMA16b3+VOlo9SYc/PnotDE/AjTe/tLl11PD5ADADWLg4MveZJDLcYzJZAPwtjKxImpK/s3SmUvX4+ZxjvBdfdSGCsOwpcB1b+ayqTG1ksTw+VIa6/Mg94S0N9we//Py6WzxN6"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(x+9\\right)=1$$",
"input": "\\frac{d}{dx}\\left(x+9\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{dx}{dx}+\\frac{d}{dx}\\left(9\\right)"
},
{
"type": "interim",
"title": "$$\\frac{dx}{dx}=1$$",
"input": "\\frac{dx}{dx}",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYko/29fz701XcRtz4b42RqRjqLYrB3CcI0Y7zGHBJCja+8ZDu8iF4MSewt4yms1lIdz2XHFZ6BxfaHSMA6lT+lbVmoiKRd+ttkZ9NIrGodT+"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(9\\right)=0$$",
"input": "\\frac{d}{dx}\\left(9\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYvTYt8V2vaKd9AkmdqaaXItJ8Vk6wvKjVnTtwWT18bQnz7FeFrf3rcM8IZlDz2c0dm5O2bEw0Ql6ne7k1AUriTsdQFf8ULyNiNWh+aczQhPx"
}
},
{
"type": "step",
"result": "=1+0"
},
{
"type": "step",
"primary": "Simplify",
"result": "=1",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{1}{2\\sqrt{x+9}}\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=\\frac{1}{2\\sqrt{x+9}}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice",
"practiceTopic": "Derivatives"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "y=\\frac{1}{2\\sqrt{x+9}}"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
derivative of
Solution
Solution steps
Apply the chain rule:
Simplify
Graph
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Frequently Asked Questions (FAQ)
What is the derivative of f(x)=sqrt(x+9) ?
The derivative of f(x)=sqrt(x+9) is 1/(2sqrt(x+9))What is the first derivative of f(x)=sqrt(x+9) ?
The first derivative of f(x)=sqrt(x+9) is 1/(2sqrt(x+9))