{
"query": {
"display": "derivative of $$y=\\ln\\left(\\sqrt{x}\\right)$$",
"symbolab_question": "PRE_CALC#derivative y=\\ln(\\sqrt{x})"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "\\frac{1}{2x}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\ln\\left(\\sqrt{x}\\right)\\right)=\\frac{1}{2x}$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(\\sqrt{x}\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}\\frac{1}{\\sqrt{x}}\\frac{d}{dx}\\left(\\sqrt{x}\\right)$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(\\sqrt{x}\\right)\\right)",
"result": "=\\frac{1}{\\sqrt{x}}\\frac{d}{dx}\\left(\\sqrt{x}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=\\ln\\left(u\\right),\\:\\:u=\\sqrt{x}$$"
],
"result": "=\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)\\frac{d}{dx}\\left(\\sqrt{x}\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)=\\frac{1}{u}$$",
"input": "\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)=\\frac{1}{u}$$",
"result": "=\\frac{1}{u}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYoqTCAmruKWcJsn66ZPDMT8cjlLRK1jUV206qo4+vRN78rEus7TgCihQBF5omOFkJq1PlbV5jLoKv9solFCc4blTW26qciuyUBGXQExCUedYd9mDo5FIvzrirtH7/W8pPUxk6YPA4jUd3Af4X0JJJ64="
}
},
{
"type": "step",
"result": "=\\frac{1}{u}\\frac{d}{dx}\\left(\\sqrt{x}\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\sqrt{x}$$",
"result": "=\\frac{1}{\\sqrt{x}}\\frac{d}{dx}\\left(\\sqrt{x}\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYrXiy6bUvhxwZcq3D6xEiUqaNohqAHcVbX8BTjr1ZRzoZ3GoG6Ko8jDPh4vymhs0+tlv8YVMwh/df5SMAfAmpJXv++bSprT8DRLjDQza+XRVtC0r1mGQza36BwJyqzDXt63CCMDvZs08hqQwvvEWeu4N5gj7/zD4e2EOslAgnMJAeqXxdc+rps1CUyb7fqI2Ga++0UXCFaDRjBhGCE8EEfmkQ/JnsM45+j77dquc6L38"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\sqrt{x}\\right)=\\frac{1}{2\\sqrt{x}}$$",
"input": "\\frac{d}{dx}\\left(\\sqrt{x}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=\\frac{d}{dx}\\left(x^{\\frac{1}{2}}\\right)",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=\\frac{1}{2}x^{\\frac{1}{2}-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{2}x^{\\frac{1}{2}-1}:{\\quad}\\frac{1}{2\\sqrt{x}}$$",
"input": "\\frac{1}{2}x^{\\frac{1}{2}-1}",
"result": "=\\frac{1}{2\\sqrt{x}}",
"steps": [
{
"type": "interim",
"title": "$$x^{\\frac{1}{2}-1}=x^{-\\frac{1}{2}}$$",
"input": "x^{\\frac{1}{2}-1}",
"steps": [
{
"type": "interim",
"title": "Join $$\\frac{1}{2}-1:{\\quad}-\\frac{1}{2}$$",
"input": "\\frac{1}{2}-1",
"result": "=x^{-\\frac{1}{2}}",
"steps": [
{
"type": "step",
"primary": "Convert element to fraction: $$1=\\frac{1\\cdot\\:2}{2}$$",
"result": "=-\\frac{1\\cdot\\:2}{2}+\\frac{1}{2}"
},
{
"type": "step",
"primary": "Since the denominators are equal, combine the fractions: $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{-1\\cdot\\:2+1}{2}"
},
{
"type": "interim",
"title": "$$-1\\cdot\\:2+1=-1$$",
"input": "-1\\cdot\\:2+1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:2=2$$",
"result": "=-2+1"
},
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-2+1=-1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s731snK5z/nd3Sq/6JpCqiX1XTSum/z5kLpMzXS1UJIew02FKSBoQo9V3G05AlnWtTyCE30rzMlUAIVDyhseMBropKGn5MuXZnb2ZCo/hVsBU="
}
},
{
"type": "step",
"result": "=\\frac{-1}{2}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Algebraic Manipulation Join Concise Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7qijEBDcyPMwV4Y1jeiGyoO0se7vRyav6BwUCJZptwG3MwViaLUXkeD+JukROhWdjQYCY06ctBCI/puUxKEtzAQH2kDe5DGYTz3TrPquGdIjtHZXPNLHlLyai31n5HH4G6M8osviUPEkWv33aMbZrSFQW3Chm7McvYpuS87Y5EFs="
}
},
{
"type": "step",
"result": "=\\frac{1}{2}x^{-\\frac{1}{2}}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-b}=\\frac{1}{a^b}$$",
"secondary": [
"$$x^{-\\frac{1}{2}}=\\frac{1}{\\sqrt{x}}$$"
],
"result": "=\\frac{1}{2}\\cdot\\:\\frac{1}{\\sqrt{x}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{1\\cdot\\:1}{2\\sqrt{x}}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:1=1$$",
"result": "=\\frac{1}{2\\sqrt{x}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79noABpxc4IZFb3O0CFaPAbH6E/qPf7AlxQDX8MXU5OsAlilG71elit3w1IBbYN0P8rEus7TgCihQBF5omOFkJrT+HVv/GE/F+xidhei/cy8B9pA3uQxmE8906z6rhnSIHimBRYRqHSWeJkuUPhfTC1O468YRFxaQeTFqgRqR2ru/qNjapxCbBfMYIYTudnDYTk5AXTHU+C+TrGKWzqT97A=="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{1}{\\sqrt{x}}\\cdot\\:\\frac{1}{2\\sqrt{x}}"
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{\\sqrt{x}}\\cdot\\:\\frac{1}{2\\sqrt{x}}:{\\quad}\\frac{1}{2x}$$",
"input": "\\frac{1}{\\sqrt{x}}\\cdot\\:\\frac{1}{2\\sqrt{x}}",
"result": "=\\frac{1}{2x}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{1\\cdot\\:1}{\\sqrt{x}\\cdot\\:2\\sqrt{x}}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:1=1$$",
"result": "=\\frac{1}{2\\sqrt{x}\\sqrt{x}}"
},
{
"type": "interim",
"title": "$$\\sqrt{x}\\cdot\\:2\\sqrt{x}=2x$$",
"input": "\\sqrt{x}\\cdot\\:2\\sqrt{x}",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}\\sqrt{a}=a$$",
"secondary": [
"$$\\sqrt{x}\\sqrt{x}=x$$"
],
"result": "=2x",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7XHME8k6dYtmAcA7S9JNIChxo++zd0ae8hIUfb3X8IwMgJ/ZZA32ZInFBpDtxBfiKaT+s2p8IB/pLWZ6wXcUGUrtCR5dIjxQ5ASg+ZPFVSscgeVeJnmIGj4+nSp9O/ygS2uawQbqk/wx6oN0dOXv7Dw=="
}
},
{
"type": "step",
"result": "=\\frac{1}{2x}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s78B+yE0cCl8hT7YErNdnZGUxSW3EOahWkuvAUg0UpmnO0/h1b/xhPxfsYnYXov3MvRXYii9G6PtJS0VMzV5tSBP2i9gqKNBiEkMJvG7+cA4kYwL9tVmLoj6d0/fLN04EQ72wZm7kDUxdE6YSmfEbr2vKTjCE2IpPTfALSHOPVsNVLzllMZAV/GQHp8dEO4L7iXEErS/oLIoC+Y1JlHSxbUlNinSirXQuGVYWiKqz93SW/Mg94S0N9we//Py6WzxN6"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice",
"practiceTopic": "Derivatives"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{1}{2x}",
"displayFormula": "y=\\frac{1}{2x}",
"derivativeFormula": "-\\frac{1}{2x^{2}}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
},
"xmax": 0,
"calculatePoints": true
},
{
"evalFormula": "y=\\frac{1}{2x}",
"displayFormula": "y=\\frac{1}{2x}",
"derivativeFormula": "-\\frac{1}{2x^{2}}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
},
"xmin": 0,
"calculatePoints": true
},
{
"evalFormula": "x=0",
"displayFormula": "y=\\frac{1}{2x}",
"attributes": {
"color": "PURPLE",
"lineType": "DASH",
"labels": [
"\\mathrm{Vertical\\:Asymptote}"
],
"isAsymptote": true
}
},
{
"evalFormula": "y=0",
"displayFormula": "y=\\frac{1}{2x}",
"attributes": {
"color": "PURPLE",
"lineType": "DASH",
"labels": [
"\\mathrm{Horizontal\\:Asymptote}"
],
"isAsymptote": true
}
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "y=\\frac{1}{2x}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -9.112499999999999,
"xMax": 9.112499999999999,
"yMin": -6.399999999999999,
"yMax": 6.399999999999999
}
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
derivative of
Solution
Solution steps
Apply the chain rule:
Simplify
Graph
Popular Examples
derivative of y=ln(x^2)derivative of derivative of f(x)=sqrt(x+9)derivative of derivative of y=x^3derivative of polar (-(9sqrt(3))/2 , 9/2)cartesian to polar derivative of xsqrt(1-x^2)derivative of
Frequently Asked Questions (FAQ)
What is the derivative of y=ln(sqrt(x)) ?
The derivative of y=ln(sqrt(x)) is 1/(2x)What is the first derivative of y=ln(sqrt(x)) ?
The first derivative of y=ln(sqrt(x)) is 1/(2x)