What is the tangent of f(x)=-3x^2-6x,\at x=-1 ?

The tangent of f(x)=-3x^2-6x,\at x=-1 is y=3

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tangent of f(x)=-3x^2-6x,\at x=-1

tangent of

f (x) = - 3 x^{2} - 6 x, at x = - 1

y = 3

Solution steps

Find the tangent point:

(- 1, 3)

Find the slope of

f (x) = - 3 x^{2} - 6 x : \frac{df ( x )}{d x} = - 6 x - 6

Compute the slope of

f (x) = - 3 x^{2} - 6 x

x = - 1 : m = 0

Find the line with slope m=

0

and passing through

(- 1, 3) : y = 3

y = 3

4 e^{x}

f (x) = π

f (x) = \frac{1}{3 x ^{2}} + 4 x^{3}

f (x) = - 12 x^{2} + 9 x, at x = 6

What is the tangent of f(x)=-3x^2-6x,\at x=-1 ?
The tangent of f(x)=-3x^2-6x,\at x=-1 is y=3