What is the derivative of f(x)= 1/(3x^2)+4x^3 ?

The derivative of f(x)= 1/(3x^2)+4x^3 is -2/(3x^3)+12x^2

What is the first derivative of f(x)= 1/(3x^2)+4x^3 ?

The first derivative of f(x)= 1/(3x^2)+4x^3 is -2/(3x^3)+12x^2

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derivative of

f (x) = \frac{1}{3 x ^{2}} + 4 x^{3}

- \frac{2}{3 x ^{3}} + 12 x^{2}

Solution steps

\frac{d}{d x} (\frac{1}{3 x ^{2}} + 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{3 x ^{2}}) + \frac{d}{d x} (4 x^{3})

\frac{d}{d x} (\frac{1}{3 x ^{2}}) = - \frac{2}{3 x ^{3}}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

= - \frac{2}{3 x ^{3}} + 12 x^{2}

f (x) = - 12 x^{2} + 9 x, at x = 6

(1.3) (3.5)

y = 5 x + 2

(6, \frac{2 π}{3})

f (x) = ln (3 x)

What is the derivative of f(x)= 1/(3x^2)+4x^3 ?
The derivative of f(x)= 1/(3x^2)+4x^3 is -2/(3x^3)+12x^2
What is the first derivative of f(x)= 1/(3x^2)+4x^3 ?
The first derivative of f(x)= 1/(3x^2)+4x^3 is -2/(3x^3)+12x^2