What is the first derivative of x^2+1 ?

The first derivative of x^2+1 is 2x

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derivative of x^2+1

derivative of

x^{2} + 1

2 x

Solution steps

\frac{d}{d x} (x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

x - 3

y = x^{l n (x)}

(- 6, 6)

f (x) = e^{\frac{1}{x}}

(7, - 12), (- 5, - 15)