{
"query": {
"display": "derivative of $$y=x^{\\ln\\left(x\\right)}$$",
"symbolab_question": "PRE_CALC#derivative y=x^{\\ln(x)}"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "\\frac{2e^{\\ln^{2}(x)}\\ln(x)}{x}",
"meta": {
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}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(x^{\\ln\\left(x\\right)}\\right)=\\frac{2e^{\\ln^{2}\\left(x\\right)}\\ln\\left(x\\right)}{x}$$",
"input": "\\frac{d}{dx}\\left(x^{\\ln\\left(x\\right)}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b}=e^{b\\ln\\left(a\\right)}$$",
"secondary": [
"$$x^{\\ln\\left(x\\right)}=e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}$$"
],
"result": "=\\frac{d}{dx}\\left(e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\right)",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)$$",
"input": "\\frac{d}{dx}\\left(e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\right)",
"result": "=e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=e^{u},\\:\\:u=\\ln\\left(x\\right)\\ln\\left(x\\right)$$"
],
"result": "=\\frac{d}{du}\\left(e^{u}\\right)\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(e^{u}\\right)=e^{u}$$",
"input": "\\frac{d}{du}\\left(e^{u}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{du}\\left(e^{u}\\right)=e^{u}$$",
"result": "=e^{u}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
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},
{
"type": "step",
"result": "=e^{u}\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\ln\\left(x\\right)\\ln\\left(x\\right)$$",
"result": "=e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)"
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},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)=\\frac{2\\ln\\left(x\\right)}{x}$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\ln\\left(x\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\ln\\left(x\\right)\\ln\\left(x\\right):{\\quad}\\ln^{2}\\left(x\\right)$$",
"input": "\\ln\\left(x\\right)\\ln\\left(x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^b\\cdot\\:a^c=a^{b+c}$$",
"secondary": [
"$$\\ln\\left(x\\right)\\ln\\left(x\\right)=\\:\\ln^{1+1}\\left(x\\right)$$"
],
"result": "=\\ln^{1+1}\\left(x\\right)",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Add the numbers: $$1+1=2$$",
"result": "=\\ln^{2}\\left(x\\right)"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{d}{dx}\\left(\\ln^{2}\\left(x\\right)\\right)"
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}2\\ln\\left(x\\right)\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)$$",
"input": "\\frac{d}{dx}\\left(\\ln^{2}\\left(x\\right)\\right)",
"result": "=2\\ln\\left(x\\right)\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=u^{2},\\:\\:u=\\ln\\left(x\\right)$$"
],
"result": "=\\frac{d}{du}\\left(u^{2}\\right)\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(u^{2}\\right)=2u$$",
"input": "\\frac{d}{du}\\left(u^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=2u^{2-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=2u",
"meta": {
"solvingClass": "Solver"
}
}
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"solvingClass": "Derivatives",
"interimType": "Derivatives",
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}
},
{
"type": "step",
"result": "=2u\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\ln\\left(x\\right)$$",
"result": "=2\\ln\\left(x\\right)\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)"
}
],
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},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)=\\frac{1}{x}$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)=\\frac{1}{x}$$",
"result": "=\\frac{1}{x}"
}
],
"meta": {
"solvingClass": "Derivatives",
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},
{
"type": "step",
"result": "=2\\ln\\left(x\\right)\\frac{1}{x}"
},
{
"type": "interim",
"title": "Simplify $$2\\ln\\left(x\\right)\\frac{1}{x}:{\\quad}\\frac{2\\ln\\left(x\\right)}{x}$$",
"input": "2\\ln\\left(x\\right)\\frac{1}{x}",
"result": "=\\frac{2\\ln\\left(x\\right)}{x}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2\\ln\\left(x\\right)}{x}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:2=2$$",
"result": "=\\frac{2\\ln\\left(x\\right)}{x}"
}
],
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"meta": {
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},
{
"type": "step",
"result": "=e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\frac{2\\ln\\left(x\\right)}{x}"
},
{
"type": "interim",
"title": "Simplify $$e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\frac{2\\ln\\left(x\\right)}{x}:{\\quad}\\frac{2e^{\\ln^{2}\\left(x\\right)}\\ln\\left(x\\right)}{x}$$",
"input": "e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}\\frac{2\\ln\\left(x\\right)}{x}",
"result": "=\\frac{2e^{\\ln^{2}\\left(x\\right)}\\ln\\left(x\\right)}{x}",
"steps": [
{
"type": "interim",
"title": "$$e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}=e^{\\ln^{2}\\left(x\\right)}$$",
"input": "e^{\\ln\\left(x\\right)\\ln\\left(x\\right)}",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\ln\\left(x\\right)\\ln\\left(x\\right):{\\quad}\\ln^{2}\\left(x\\right)$$",
"input": "\\ln\\left(x\\right)\\ln\\left(x\\right)",
"result": "=e^{\\ln^{2}\\left(x\\right)}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^b\\cdot\\:a^c=a^{b+c}$$",
"secondary": [
"$$\\ln\\left(x\\right)\\ln\\left(x\\right)=\\:\\ln^{1+1}\\left(x\\right)$$"
],
"result": "=\\ln^{1+1}\\left(x\\right)",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Add the numbers: $$1+1=2$$",
"result": "=\\ln^{2}\\left(x\\right)"
}
],
"meta": {
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
}
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},
{
"type": "step",
"result": "=e^{\\ln^{2}\\left(x\\right)}\\frac{2\\ln\\left(x\\right)}{x}"
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{2\\ln\\left(x\\right)e^{\\ln^{2}\\left(x\\right)}}{x}"
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Solution
derivative of
Solution
Solution steps
Apply exponent rule:
Apply the chain rule:
Simplify
Graph
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Frequently Asked Questions (FAQ)
What is the derivative of y=x^{ln(x)} ?
The derivative of y=x^{ln(x)} is (2e^{ln^2(x)}ln(x))/xWhat is the first derivative of y=x^{ln(x)} ?
The first derivative of y=x^{ln(x)} is (2e^{ln^2(x)}ln(x))/x